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2 years ago

PLS HELP ASAP DOING A TEST What is the diameter of a plate with circumference of 25 cm.?

Mathematics

1 answer:

Alexeev081 [22]2 years ago

8 0

Answer:

7.95

Step-by-step explanation:

:) I did it first

I commented because the spot was taken at the moment

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In triangle Xyz the measure of angle YXZ is 14.5°, and the measure of angle XYZ is 75°. What is the measure of angle XZY in degr

steposvetlana [31]

Answer:

90.5 degrees

Step-by-step explanation:

The sum of the angle in triangle XYZ is 180 degrees, hence;

m<XYZ + m<YXZ + <XZY = 180

Substitute the given angles

75 + 14.5 + <XZY = 180

89.5+m<XZY = 180

m<XZY = 180 - 89.5

m<XZY = 90.5 degrees

Hence the measure of angle XZY in degrees is 90.5 degrees

7 0

2 years ago

45 is 60% percent of what number

trasher [3.6K]

The answer is 75 as you would divide 45 by 0.6

5 0

2 years ago

Let a and b be roots of x² - 4x + 2 = 0. find the value of a/b² +b/a²

erastovalidia [21]

Answer:

$\dfrac{a}{b^2}+\dfrac{b}{a^2}=10$

Step-by-step explanation:

Given equation: $x^2-4x+2=0$

The roots of the given quadratic equation are the values of x when $y=0$ .

To find the roots, use the quadratic formula:

$x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0$

Therefore:

$a=1, \quad b=-4, \quad c=2$

$\begin{aligned}\implies x & =\dfrac{-(-4) \pm \sqrt{(-4)^2-4(1)(2)}}{2(1)}\\& =\dfrac{4 \pm \sqrt{8}}{2}\\& =\dfrac{4 \pm 2\sqrt{2}}{2}\\& =2 \pm \sqrt{2}\end{aligned}$

$\textsf{Let }a=2+\sqrt{2}$

$\textsf{Let }b=2-\sqrt{2}$

Therefore:

$\begin{aligned}\implies \dfrac{a}{b^2}+\dfrac{b}{a^2} & = \dfrac{2+\sqrt{2}}{(2-\sqrt{2})^2}+\dfrac{2-\sqrt{2}}{(2+\sqrt{2})^2}\\\\& = \dfrac{2+\sqrt{2}}{6-4\sqrt{2}}+\dfrac{2-\sqrt{2}}{6+4\sqrt{2}}\\\\& = \dfrac{(2+\sqrt{2})(6+4\sqrt{2})+(2-\sqrt{2})(6-4\sqrt{2})}{(6-4\sqrt{2})(6+4\sqrt{2})}\\\\& = \dfrac{12+8\sqrt{2}+6\sqrt{2}+8+12-8\sqrt{2}-6\sqrt{2}+8}{36+24\sqrt{2}-24\sqrt{2}-32}\\\\& = \dfrac{40}{4}\\\\& = 10\end{aligned}$