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Phantasy [73]
3 years ago
11

Please help me understand

Mathematics
1 answer:
xeze [42]3 years ago
5 0

Step-by-step explanation:

A=2(wl+hl+hw)=2x(14x7+7x7+7x14)=490

Option B is the correct answer

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Are 5/8 and 4/7 proportional
artcher [175]

Answer:no

Step-by-step explanation:

5 0
3 years ago
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Line t has slope 3/4 and passes through (0, 0) . Follow these steps:Step
mina [271]

Answer:

(8,0)

Step-by-step explanation:

y=mx+b

0=(3/4)0+b

0=b

y=3/4x+0

the point eight units away from (0,0)

is (8,0)

Hope this helps :)

7 0
3 years ago
Which of the following represents the prime factorization of 72?
Free_Kalibri [48]

Answer:

2^3.3^2

Step-by-step explanation:

{2}^{3 ?}  = 8 \\  {?3}^{2?}  = 9 \\ 8 \times 9 = 72

7 0
3 years ago
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Could some please help and explain?
Sophie [7]

Answer:

x = 7

Step-by-step explanation:

A rhombus is a parallelogram where all sides are equal. Therefore, as we know two sides are equal to 7x+8 and 9x-6, we can say that

7x+8 = 9x - 6

subtract 7x from both sides to put the variable on one side

2x - 6 = 8

add 6 to both sides to isolate the variable and its coefficient

2x = 14

divide both sides by 2 to isolate x

x = 7

7 0
2 years ago
Which equation represents the equation of the parabola with focus (-3 3) and directrix y=7?
Artemon [7]

Answer:

The equation y=\frac{-x^2-6x+31}{8} represents the equation of the parabola with focus (-3, 3) and directrix y = 7.

Step-by-step explanation:

To find the equation of the parabola with focus (-3, 3) and directrix y = 7. We start by assuming a general point on the parabola (x, y).

Using the distance formula d = \sqrt {\left( {x_1 - x_2 } \right)^2 + \left( {y_1 - y_2 } \right)^2 }, we find that the distance between (x, y) is

\sqrt{(x+3)^2+(y-3)^2}

and the distance between (x, y) and the directrix y = 7 is

\sqrt{(y-7)^2}.

On the parabola, these distances are equal so, we solve for y:

\sqrt{(x+3)^2+(y-3)^2}=\sqrt{(y-7)^2}\\\\\left(\sqrt{\left(x+3\right)^2+\left(y-3\right)^2}\right)^2=\left(\sqrt{\left(y-7\right)^2}\right)^2\\\\x^2+6x+y^2+18-6y=\left(y-7\right)^2\\\\x^2+6x+y^2+18-6y=y^2-14y+49\\\\y=\frac{-x^2-6x+31}{8}

6 0
3 years ago
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