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klemol [59]
3 years ago
9

What is the enthalpy of reaction for the decomposition of calcium carbonate? CaCO3(s) Right arrow. CaO(s) CO2(g) kJ.

Chemistry
1 answer:
In-s [12.5K]3 years ago
8 0

The enthalpy of reaction for the decomposition of calcium carbonate is 177.4  KJ/mole .

We know that the enthalpy of reaction can be obtained from the enthalpy of formation of the reactants and that of the products using the formula;

ΔHrxn = ΔHf (products) - ΔHf (reactants)

The heat of formation of the species are as follows;

ΔHf (CaCO3(s)) = −1206.9 KJ/mol

ΔHf (CaO(s)) =  - 636 KJ/mole

ΔHf (CO2(g)) = -393.5  KJ/mole

ΔHrxn = [( -393.5  KJ/mole ) + ( - 636 KJ/mole)] - [ −1206.9 KJ/mol]

ΔHrxn = 177.4  KJ/mole

Learn more: brainly.com/question/13164491

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