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77julia77 [94]
3 years ago
12

1. In any nuclear reaction, nuclei are transformed in some way.

Chemistry
2 answers:
Anna71 [15]3 years ago
5 0

Answer:

1. True

2. true

3. True

4. False

Explanation:

1. In nuclear reaction, the nuclie are transformed to produce a large amount of energy. In fission reaction, one large nucleus breaks to form two small nucleus and produce energy. In fusion reaction,two nucleus combine to form a single large nucleus.

2. Uranium 235 used in nuclear reaction absorbs neutrons and form two smaller nucleus to produce  large amount of energy.

              Plutonium-239 also absorb neutrons and also fission with uranium-235 in a reactor.

3. Fusion reaction is uncontrollable. It occurs in the sun. It is a chain reaction which produce more and more energy along with neutrons. So it is uncontrollable.

Whereas , Fission reaction is controllable by using controlled rods.

4. Fusion reaction occurs at the sun to produce high temperature and energy and the sun glows.

Grace [21]3 years ago
4 0
<span>1. In any nuclear reaction, nuclei are transformed in some way.

True

2. Two fissionable substances commonly used in nuclear reactors and nuclear weapons include uranium-235 and plutonium-239.

True

3. Fission reactions can be controlled; thus, they are used to create energy and electricity. But fusion reactions are uncontrollable and require too much energy for economical use.

True

4. Fission reactions occur at such high temperatures in the Sun that the Sun appears to glow.

False

Hope this answers the question. Have a nice day.</span>
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Answer:

about 3 miles i think

Explanation:

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g A microwave oven heats by radiating food with microwave radiation, which is absorbed by the food and converted to heat. If the
Sliva [168]

Answer:

The total photons required = 5.19 × 10²⁸ photons

Explanation:

Given that:

the radiation wavelength λ= 12.5 cm = 0.125 m

Volume of the container = 0.250 L = 250 mL

The density of water = 1 g/mL

Density = mass /volume

Mass =  Volume ×  Density

Thus; the mass of the water =  250 mL ×  1 g/mL

the mass of the water = 250 g

the specific heat of water s = 4.18 J/g° C

the initial temperature T_1 = 20.0° C

the final temperature T_2 = 99° C

Change in temperature \Delta T = (99-20)° C = 79 ° C

The heat q absorbed during the process = ms \Delta T

The heat q absorbed during the process = 250 g × 4.18 J/g° C × 79° C

The heat q absorbed during the process = 82555 J

The energy of a photon can be represented by the equation :

= hc/λ

where;

h = planck's constant = 6.626 \times 10^{-34} \ J.s

c = velocity of light = 3.0 \times 10^8 \ m/s

=  \dfrac{6.626 \times 10^{-34} \times 3.0 \times 10^8}{0.125}

= 1.59024 \times 10^{-24} J

The total photons required = Total heat energy/ Energy of a photon

The total photons required = \dfrac{82555 J}{1.59024 \times 10^{-24}J}

The total photons required = 5.19 × 10²⁸ photons

5 0
3 years ago
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Answer:

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Phosphorous trichloride and phosphorous pentachloride equilibrate in the presence of molecular chlorine according to the reactio
umka21 [38]

Answer : The value of K_p at this temperature is 66.7

Explanation : Given,

Pressure of PCl_3 at equilibrium = 0.348 atm

Pressure of Cl_2 at equilibrium = 0.441 atm

Pressure of PCl_5 at equilibrium = 10.24 atm

The balanced equilibrium reaction is,

PCl_3(g)+Cl_2(g)\rightleftharpoons PCl_5(g)

The expression of equilibrium constant K_p for the reaction will be:

K_p=\frac{(p_{PCl_5})}{(p_{PCl_3})(p_{Cl_2})}

Now put all the values in this expression, we get :

K_p=\frac{(10.24)}{(0.348)(0.441)}

K_p=66.7

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4 0
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