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horrorfan [7]
2 years ago
13

A marine biologist and her team capture 56 sea turtles and mark them before releasing them. The following year, they capture 45

sea turtles at the same location. Of the 45 sea
turtles, only 20 have the mark from the prior year. What is the estimated population of sea turtles for that location?

A 25 sea turtles
B 126 sea turtles
C 160 sea turtles
D 240 sea turtles
Biology
2 answers:
Vadim26 [7]2 years ago
5 0

Answer:

B

Explanation:

OLga [1]2 years ago
5 0

Answer:

It would be 126(B)

Explanation:

because the "equation" to solve this problem would be to multiply 56 and 45 then with that total divide by 20.

It's the mark- return-recapture method. Ecologists use it to calculate the estimated population of biodiversity

also I did the test and it was right!

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Animals require certain amino acids on their diet, an amino acid that is referred to as nonessential would be best described as
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Crawfish are shelled organisms that live in shallow freshwater rivers. They can have antennae of different lengths. Two parents
vredina [299]

The phenotype of antenna in crawfish depends on the protein amount in the antenna length. The offspring have different phenotype than their parent because of the amount of protein translated from each parent gene is determining in this.

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Explanation:

Data given:

Two crawfish parent = medium length antennae, genotyoe Ll

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The traits in offspring is shown as:

       L    l

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The proportion of allele present in the gene determined the length of the antenna in crawfish.

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yaroslaw [1]

im not even sure tbh these are really hard im so sorry

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