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sleet_krkn [62]
2 years ago
5

Consider the chart describing the element. According to the chart, the element is _______ with an atomic number of ___________.

Question 8 options: neon; 3 boron; 4 lithium; 3 nitrogen; 7.
Chemistry
1 answer:
Marysya12 [62]2 years ago
4 0

The periodic table is known to consist of different elements. According to the chart, the element is lithium with an atomic number of 3.

  • Lithium is known too be the third element on the periodic table after hydrogen and helium.

This element is mostly used in the production of rechargeable batteries for mobile phones, laptops, etc. and it is also used  non-rechargeable batteries for production of heart pacemakers, toys, etc.

Learn more from

brainly.com/question/11211163

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Answer 14 and 18 please
Allushta [10]
14 is C but I cannot see the other one
4 0
3 years ago
Sort these isotopes by whether they are most likely to undergo fusion or fission.
Maslowich

Answer:

Uranium-233- fission

Plutonium-239- fission

Plutonium-241- fission

Hydrogen-3 fusion

Hydrogen-1 fusion

Helium-3 fusion

Explanation:

In nuclear fission, heavy nuclear disintegrate into smaller nuclei when bombarded with particles such as neutrons. Fission reaction is common among nuclei having a high atomic number such as plutonium and uranium.

Fusion occurs between two light nuclei such as hydrogen or helium. It involves the combination of two lighter elements to give a heavier element with the release of tremendous amount of energy.

4 0
3 years ago
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klemol [59]

the answer is Nitrogen.

7 0
3 years ago
A gas has a temperature of 12 C and a volume of 3.5 L if the temperature is raised to 29C in the pressure is not altered what is
Nataly_w [17]
The answer is V2=3.71
8 0
4 years ago
Calculate the pH during the titration of 30.00 mL of 0.1000 M HCOOH(aq) with 0.1000 M NaOH(aq) after 29.3 mL of the base have be
pashok25 [27]

Answer:

3.336.

Explanation:

<em>Herein, the no. of millimoles of the acid (HCOOH) is more than that of the base (NaOH).</em>

<em />

So, <em>concentration of excess acid = [(NV)acid - (NV)base]/V total</em> = [(30.0 mL)(0.1 M) - (29.3 mL)(0.1 M)]/(59.3 mL) = <em>1.18 x 10⁻³ M.</em>

<em></em>

<em> For weak acids; [H⁺] = √Ka.C</em> = √(1.8 x 10⁻⁴)(1.18 x 10⁻³ M) = <em>4.61 x 10⁻⁴ M.</em>

∵ pH = - log[H⁺].

<em>∴ pH = - log(4.61 x 10⁻⁴) = 3.336.</em>

7 0
4 years ago
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