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vodomira [7]
3 years ago
5

In preparation for a demonstration, your professor brings a 1.50−L bottle of sulfur dioxide into the lecture hall before class t

o allow the gas to reach room temperature. If the pressure gauge reads 988 psi and the lecture hall is 25°C, how many moles of sulfur dioxide are in the bottle? In order to solve this problem, you will first need to calculate the pressure of the gas. Hint: The gauge reads zero when 14.7 psi of gas remains.
Chemistry
1 answer:
solmaris [256]3 years ago
4 0

Answer:

4.81 moles

Explanation:

The total pressure of the gas = Pressure at which gauge reads zero + pressure read by it.

Pressure at which gauge reads zero = 14.7 psi

Pressure read by the gauge = 988 psi

Total pressure = 14.7 + 988 psi = 1002.7 psi

Also, P (psi) = P (atm) / 14.696

Pressure = 1002.7 / 14.696  = 68.2297 atm

Temperature = 25 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T = (25 + 273.15) K = 298.15 K  

Volume = 1.50 L

Using ideal gas equation as:

PV=nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

68.2297 atm × 1.5 L = n × 0.0821 L.atm/K.mol × 298.15 K  

⇒n = 4.81 moles

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Fe2O3 + CO --> Fe + CO2
satela [25.4K]

Answer:

The answer to your question is

1.-Fe₂O₃

2.- 280 g

3.- 330 g

Explanation:

Data

mass of CO = 224 g

mass of Fe₂O₃ = 400 g

mass of Fe = ?

mass of CO₂

Balanced chemical reaction

                       Fe₂O₃   + 3CO    ⇒  2Fe  +   3CO₂

1.- Calculate the molar mass of Fe₂O₃ and CO

Fe₂O₃ = (56 x 2) + (16 x 3) = 160 g

CO = 12 + 16 = 28 g

2.- Calculate the proportions

theoretical proportion Fe₂O₃ /3CO = 160/84 = 1.90

experimental proportion Fe₂O₃ / CO = 400/224 = 1.78

As the experimental proportion is lower than the theoretical, we conclude that the Fe₂O₃ is the limiting reactant.

3.-     160 g of Fe₂O₃  --------------- 2(56) g of Fe

         400 g of Fe₂O₃ ---------------  x

         x = (400 x 112) / 160

        x = 280 g of Fe

4.-      160 g of Fe₂O₃  --------------- 3(44) g of CO₂

          400 g of Fe₂O₃  --------------  x

          x = (400 x 132)/160

         x = 330 gr

3 0
3 years ago
Silicon reacts with carbon dioxide to form silicon carbide sic and silicon dioxide
andrew-mc [135]

The question is incomplete, here is the complete question:

Silicon reacts with carbon dioxide to form silicon carbide and silicon dioxide. Write the balanced chemical equation.

<u>Answer:</u> The balanced chemical equation is written below.

<u>Explanation:</u>

Every balanced chemical equation follows law of conservation of mass.

A balanced chemical equation is defined as the equation in which total number of individual atoms on the reactant side is equal to the total number of individual atoms on product side.

The balanced chemical equation for the reaction of silicon and carbon dioxide follows:

2Si+CO_2\rightarrow SiC+SiO_2

By Stoichiometry of the reaction:

2 moles of silicon reacts with 1 mole of carbon dioxide gas to produce 1 mole of silicon carbide and 1 mole of silicon dioxide

Hence, the balanced chemical equation is written above.

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3 years ago
(a) What property is used today for the order of the elements?
Gennadij [26K]

Answer:

I feel as though you are missing information to this question.

Explanation:

elements on the periodic table, today, are arranged based on physical properties, such as valence electrons, atomic mass, etc.

3 0
2 years ago
How many atoms are in 3 moI of helium
disa [49]
Mark Brainiest please

Answer:
1.8 x 10^24

One mole of helium has 6.02 x 10^23 atoms, thise number is also called Avogadro's number or constant.
If we need number of atoms for 3 moles so simply, multiply 3 by 6.02 x 10^23
so,
Number of atoms for 3 moles = 3 x ()
Number of atoms will be = 1.806x10^24
5 0
3 years ago
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In which type of chemical reaction due to a more reactants combined to form one product only
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Synthesis or a combination reaction. Two of the reactants form one final product in the end.

8 0
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