Answer:
It helps shape, while holding and keeping organelles in their place.
Explanation:
Answer:
Explanation:
A sound knowledge of specific heat capacity of the metals is required in this case.
The specific heat capacity of a metal is the quantity of heat required to the raise the temperature of a unit mass of it by 1°C.
It is related to quantity of heat using the expression below;
H = m c Δt
where m is the mass
c is the specific heat capacity
Δt is the temperature change
let us make the specific the subject of the expression;
c = ![\frac{H}{m x change in temperature}](https://tex.z-dn.net/?f=%5Cfrac%7BH%7D%7Bm%20x%20change%20in%20temperature%7D)
we can see that there is an inverse relationship between specific heat and temperature change.
The specific heat capacity of a body is an intensive property that is unique to the metal.
The higher the specific heat capacity, the lower the amount of temperature change in it.
Let us find the specific heat capacity of the given metals;
Aluminium 0.897J/gK
Iron 0.412J/gK
Silver 0.24J/gK
After the heat is supplied,
Silver > Iron > Aluminium in terms of temperature change
<span>For equation A + 3B + 2C ---> 2D,
1 mole of A will produce 2 moles of D
3 moles of B will produce 2 moles of D, so 1 mole of B will produce 2/3 moles of D
2 moles of C will produce 2 moles of D, so 1 mole of C will produce 1 mole of D
If only 1 mole of B is present, only 2/3 moles of D can be produced. This is regardless of the number of moles of A and C. B is the limiting reactant and the maximum number of moles of D expected is 2/3.</span>
Answer:
The molecular formula is C12H18O3
Explanation:
Step 1: Data given
The empirical formula is C4H6O
Molecular weight is 212 g/mol
atomic mass of C = 12 g/mol
atomic mass of H = 1 g/mol
atomic mass of O = 16 g/mol
Step 2: Calculate the molar mass of the empirical formula
Molar mass = 4* 12 + 6*1 +16
Molar mass = 70 g/mol
Step 3: Calculate the molecular formula
We have to multiply the empirical formula by n
n = the molecular weight of the empirical formula / the molecular weight of the molecular formula
n = 70 /212 ≈ 3
We have to multiply the empirical formula by 3
3*(C4H6O- = C12H18O3
The molecular formula is C12H18O3