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horrorfan [7]
3 years ago
9

Please help I’ll mark you as brainliest if correct!

Mathematics
1 answer:
skad [1K]3 years ago
4 0

Answer: 96, 192, and 384

Step-by-step explanation:

It keeps doubling 48 + 48, 96 + 96, 192 + 192

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Help pls I need it now
Naddik [55]

Answer and Step-by-step explanation:

So, the format you should choose is the second one.

This is what goes in each box:

[4] (p - [6]) = [12]

The 4 is multiplying the price for 1 of the items (and it is 4 because there are 4 items), the 6 is taking away 6 dollars (because coupons take away money from amount) and 12 is the total amount of money.

Now, we solve for <u>p</u>.

Divide each side by 4.

p - 6 = 3

Now, add 6 to each side.

p = 9.

Each item cost 9 dollars.

<em><u>#teamtrees #PAW (Plant And Water)</u></em>

8 0
3 years ago
The product of four numbers, a,b,c,d, is a negative number. The table shows on combination of positive and negative signs of the
Iteru [2.4K]

Product of odd number of negative terms is negative.

Hence, I have given all the 8 possibilities.

Please refer to the table attached.

5 0
3 years ago
a random sample of 4 claims are selected from a lot of 12 that has 3 nonconforming units. using the hypergeometric distribution
Sloan [31]

Answer:

The probability that the sample will contain exactly 0 nonconforming units is P=0.25.

The probability that the sample will contain exactly 1 nonconforming units is P=0.51.

.

Step-by-step explanation:

We have a sample of size n=4, taken out of a lot of N=12 units, where K=3 are non-conforming units.

We can write the probability mass function as:

P(x=k)=\frac{\binom{K}{k}\binom{N-K}{n-k}}{\binom{N}{n}}

where k is the number of non-conforming units on the sample of n=4.

We can calculate the probability of getting no non-conforming units (k=0) as:

P(x=0)=\frac{\binom{3}{0}\binom{9}{4}}{\binom{12}{4}}=\frac{1*126}{495}=\frac{126}{495} = 0.25

We can calculate the probability of getting one non-conforming units (k=1) as:

P(x=1)=\frac{\binom{3}{1}\binom{9}{3}}{\binom{12}{4}}=\frac{3*84}{495}=\frac{252}{495} = 0.51

5 0
3 years ago
(8x 2 −15x)−(x 2 −27x)=ax 2 +bxleft parenthesis, 8, x, squared, minus, 15, x, right parenthesis, minus, left parenthesis, x, squ
quester [9]

Answer:

<h2>5</h2>

Step-by-step explanation:

Given the expression (8x² −15x)−(x² −27x) = ax² +bx, we are to determine the value of b-a. Before we determine the vwlue of b-a, we need to first calculate for the value of a and b from the given expression.

On expanding the left hand side of the expression we have;

= (8x² −15x)−(x² −27x)

Open the paranthesis

= 8x² −15x−x²+27x

collect the like terms

= 8x²−x²+27x −15x

=  7x²+12x

Comparing the resulting expression with ax²+bx

7x²+12x =  ax²+bx

7x² = ax²

a = 7

Also;

12x = bx

b =12

The value of b - a = 12 - 7

b -a = 5

Hence the value of b-a is equivalent to 5

3 0
3 years ago
Will the product be greater or less then each factor? 56.9×2.01
g100num [7]
Hmmmt that’s a good question
8 0
3 years ago
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