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fenix001 [56]
2 years ago
14

If you move at 50 meters in 10 seconds, what is your speed?

Chemistry
1 answer:
Readme [11.4K]2 years ago
5 0

Answer:

5 M/S

Explanation:

I think this is correct

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When molten material hardens and cools, what type of rock is formed?
kirza4 [7]
Should be an igneous rock.
7 0
3 years ago
How many of the following molecules have sp2 hybridization on the central atom? hcn so2 ocl2 xecl2.
GrogVix [38]

Only one molecule have <u>sp2 </u>hybridization on central atom and that is <u>SO₂</u>.

<u>XeCl₂</u> have <u>sp3d </u>hybridization.

<u>OCl₂</u> have <u>sp3 </u>hybridization.

<u>HCN </u>have <u>sp </u>hybridization.

Hybridization is defined as the concept of mixing two atomic orbitals to give rise to a new type of hybridized orbitals.

Hybridization intermixing usually results in the formation of hybrid orbitals having entirely different energies, shapes, etc.

Learn more about hybridization here:- brainly.com/question/22765530

#SPJ4

7 0
1 year ago
In pure water at 25 °C, the concentration of a saturated solution of CuF2 is 7.4 × 10−3 M. If measured at the same temperature,
Romashka-Z-Leto [24]

Answer:

The concentration of a saturated solution of CuF₂ in aqueous 0.20 M NaF is  4.0×10⁻⁵ M.

Explanation:

Consider the ICE take for the solubility of the solid, CuF₂ as:

                                  CuF₂    ⇄     Cu²⁺ +    2F⁻

At t=0                            x                 -              -

At t =equilibrium      (x-s)                s           2s          

The expression for Solubility product for CuF₂ is:

K_{sp}=\left [ Cu^{2+} \right ]\left [ F^- \right ]^2

K_{sp}=s\times {2s}^2

K_{sp}=4s^3

Given  s = 7.4×10⁻³ M

So, Ksp is:

K_{sp}=4\times (7.4\times 10^{-3})^3

K_{sp}=4\times (7.4\times 10^{-3})^3

Ksp = 1.6209×10⁻⁶

Now, we have to calculate the solubility of CuF₂ in NaF.

Thus, NaF already contain 0.20 M F⁻ ions

Consider the ICE take for the solubility of the solid, CuF₂ in NaFas:

                                  CuF₂    ⇄     Cu²⁺ +    2F⁻

At t=0                            x                 -            0.20

At t =equilibrium      (x-s')             s'         0.20+2s'         

The expression for Solubility product for CuF₂ is:

K_{sp}=\left [ Cu^{2+} \right ]\left [ F^- \right ]^2

1.6209\times 10^{-6}={s}'\times ({0.20+2{s}'})^2

Solving for s', we get

<u>s' = 4.0×10⁻⁵ M</u>

<u>The concentration of a saturated solution of CuF₂ in aqueous 0.20 M NaF is  4.0×10⁻⁵ M.</u>

3 0
4 years ago
What instrument should be used to find liquid volume?
timurjin [86]
Volumetric Cylinders
6 0
3 years ago
Read 2 more answers
"Do you own a dog?" might be an example of which concept?
Anna11 [10]

C: Control Question

Have a good day :)

6 0
3 years ago
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