Answer:
mass of Zn = 77.0 g
Explanation:
In the sample you have the same moles of Zn and Ga.
The formula for moles is:
![Mass = moles*MM \\](https://tex.z-dn.net/?f=Mass%20%3D%20moles%2AMM%20%5C%5C)
Where MM: Molar Mass or Atomic Mass for elements
AM(Ga) = 69.723 amu
AM(Zn) = 65.38 amu
moles of Ga = ![\frac{Mass}{AM} = \frac{82.1 g}{69.723 amu} = 1.178 mole](https://tex.z-dn.net/?f=%5Cfrac%7BMass%7D%7BAM%7D%20%3D%20%5Cfrac%7B82.1%20g%7D%7B69.723%20amu%7D%20%3D%201.178%20mole)
mass of Zn = ![moles*AM=1.178 mole*65.38amu = 77.0 g](https://tex.z-dn.net/?f=moles%2AAM%3D1.178%20mole%2A65.38amu%20%3D%2077.0%20g)
The answer is 2.75 because you divide 22 by 8
Answer:
With regards to the final composition of the mixture in the vessel at equilibrium, there will be very little amount of the reactants (BrOCl and BrCl), since some amounts of each have been used to form the products (Br2 and OCl).
zero i think because the compound is both put together... right?