.I like being spontaneous on the job.

You move 18% of your online checking account balance of $2,525 to your savings account. How much of your checking account did yo

dusya [7]

Answer:

$454.50

Explanation:

18% X $2525 = $454.5

8 0

4 years ago

A factory costs $400,000. It will produce an inflow after operating costs of $100 000 in year 1. $ 200,000 in year 2, and $ 300,

Delvig [45]

Answer:

NPV = $62,258.56

Explanation:

initial outlay year 0 = $400,000

cash inflow year 1 = $100,000

cash inflow year 2 = $200,000

cash inflow year 3 = $300,000

discount rate = 12%

using a financial calculator, NPV = $62,258.56

if you do it by hand:

NPV = -$400,000 + $100,000/1.12 + $200,000/1.12² + $300,000/1.12³ = -$400,000 + $89,285.71 + $159,438.78 + $213,534.07 = $62,258.56

3 0

3 years ago

At the profit maximizing level of employment, the wage rate is _____ and the level of employment is _____: w3; q1 w2; q2 w1; q1

diamong [38]

The correct option is w1;q1.
At the profit maximizing level of employment, the wage rate is W1 and the level of employment is Q1.

4 0

4 years ago

Fern invested $6400 into a continuously compounded account with an interest rate of 1.5%. After 10 years, how much is the accoun

777dan777 [17]

Answer:

FV= $7,435.74

Explanation:

Giving the following information:

Initial investment= $6,400

Interest rate= 1.5%

Number of periods= 10 years

To calculate the value of the account in ten years, we need to use the following formula:

FV= PV*e^(i*n)

FV= 6,400*e^(0.015*10)

FV= $7,435.74

6 0

3 years ago

The Centers for Disease Control and Prevention (CDC) defines a healthy sleep duration

laiz [17]

a. The point estimate of the married people that sleep well is = 0.6299. The confidence interval for the mean hours of sleep for those that have never been married but report good sleep is 0.6186, 0.6412

b. The point estimate of the number of hours for people that have never been married = 7.2257

95% confidence interval for the mean number of hours of sleep for those who have never been married = 7.2065, 7.2447

c. the estimated number of sleep for those that have never been married = 7.729 hours

a. The point estimate

$P=\frac{Xp}{n}$

$Xp = successes\\n = sample size\\$

Those who have never been married n = 7044

Xp = those who sleep for 7 hours at least

To get Xp, the excel function

Countif(range, criteria)

Countif(A:A, >=7)

This gives Xp = 4437

Point estimate =

$\frac{4477}{7044}$

= 0.6299

The point estimate of the married people that sleep well is = 0.6299

At 95% interval of confidence,

α = 1-0.95 = 0.05

α/2 = 0.05/2 = 0.025

Z0.025 = 1.96 ( Use the standard probability normal table)

Margin of Error

= $M.E = 1.96\sqrt \frac{0.6299(1-0.6299)}{7044} \\\\= 1.96\sqrt{0.000033} \\\\1.96*0.0057$

= 0.0113

The 95% confidence interval

= 0.6299 - 0.0113 , 0.6299 + 0.0113

= 0.6186, 0.6412

The confidence interval for the mean hours of sleep for those that have never been married is 0.6186, 0.6412

b. Sample mean

x = ∑x/n

x = number of sleep of the never been married

Mean is calculated using excel function

Average(range)

Average(a:a)

This gives the sample mean = 7.2257

The point estimate of the number of hours for people that have never been married = 7.2257

Standard deviation using excel =

Stdev(A:A) = 0.8211

$Margin of error =1.96*\frac{0.8211}{\sqrt{7044} }$

= 0.0192

The confidence interval =

= 7.2257-0.0192, 7.2257+0.0192

= 7.2065, 7.2447

95% confidence interval for the mean number of hours of sleep for those who have never been married = 7.2065, 7.2447

c. From the available data, the mean number of sleep per day that is gotten from the 4437 people that are unmarried and sleep healthily for at least 7 hours = 34295.1

Mean = 34295.1/4437

= 7.729

the estimated number of sleep for those that have never been married = 7.729 hours

6 0

3 years ago