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Ray Of Light [21]
3 years ago
6

In the reaction 2HgO(s) --> 2Hg(l) + O2(g) we measure the evolution of gas to determine the rate of reaction. At the beginnin

g of the reaction (at 0 minutes), 0.02 L of O2 is present. After 10 minutes the volume of O2 is 0.36 L. What is the rate of reaction? Question 4 options:
Mathematics
1 answer:
djverab [1.8K]3 years ago
4 0

Answer:

0.034 L/min

Step-by-step explanation:

The rate of reaction is the volume change (ΔV) divided by the time(t) and divided by the coefficient of the compound in the reaction. The coefficient of O₂ is 1, so:

R = (0.36 - 0.02)/10

R = 0.034 L/min

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Day care centers expose children to a wider variety of germs than the children would be exposed to if they stayed at home more o
Ostrovityanka [42]

Answer:

a) The study is an observational study

b) The proportion of children with significant social activity in children with acute lymphoblastic leukemia is approximately 0.802

The proportion of children with significant social activity in children without acute lymphoblastic leukemia is approximately 0.8565

c) The odds ratio is approximately 0.6780

d) The 95% CI is approximately 0.523 < OR < 0.833

e) i) Yes

ii) Children with more social activity have a higher occurrence of acute lymphoblastic leukemia

Step-by-step explanation:

a) An experimental study is a study in which the researcher adds inputs to the study and then monitors the outcomes

An observational study is one in which the researcher observes risk factors and does not intervene in the process

Therefore, the study is an observational study

b) The proportion of children with significant social activity in children with acute lymphoblastic leukemia is \hat p_1 = 1020/1272 = 85/106 = 0.8\overline {0188679245283} ≈ 0.802

The proportion of children with significant social activity in children without acute lymphoblastic leukemia is \hat p_2 = 5343/6238 ≈ 0.8565

c) We have the following two way table;

\begin{array}{ccc}Lymphoblastic \ Leukemia &With \ Social \ Activity & Without \ Social \ Activity\\With&1020 \ (a)&252 \ (b)\\Without&5343 \ (c)&895 \ (d) \end{array}

The \ odds \ ratio = \dfrac{1,020 \times 895}{5,343 \times 252} \approx 0.6780

The odds ratio ≈ 0.6780

d) The 95% confidence interval for the odds ratio is given as follows;

95 \% \ CI = OR \ \pm \ 1.96 \times \sqrt{\dfrac{1}{a} +\dfrac{1}{b}+\dfrac{1}{c}+\dfrac{1}{d}}

Where;

a = 1020, b = 252, c = 5343, d = 895

Therefore;

95 \% \ CI \approx  0.6780 \ \pm \ 1.96 \times \sqrt{\dfrac{1}{1,020} +\dfrac{1}{252}+\dfrac{1}{5,343}+\dfrac{1}{895}} \approx 0.678 \pm0.155

The 95% CI ≈ 0.523 < OR < 0.833

e) i) Given that the observed Odds Ratio is within the Confidence Interval, therefore, there is an indication that the amount of social activity is associated with acute lymphoblastic leukemia

ii) Based on the proportion of the study findings, children with more social activity have a higher occurrence of acute lymphoblastic leukemia

6 0
3 years ago
17% of 51 is what number <br> I WILL GIVE BRAINLIEST
kramer

Answer:

8.67

Step-by-step explanation:

(using proportion method)

51 * 17 = 867

100 * x = 100x

867 / 100x = 8.67

7 0
3 years ago
Tom has 28 milk chocolates and emily has 24 dark chocolates they have to divide these chocolates into small packets that each ha
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Answer: the maximum number of packets they can make i 4 packets to make the maximum number of packets, each packet should have 7 milk chocolates and 6 dark chocolates. If that does not work then there can be 2 packets with 14 milk chocolates and 12 dark chocolates.

Step-by-step explanation:

This is hurting my brain ngl

Hope this helps though ;)

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