In the reaction 2HgO(s) --> 2Hg(l) + O2(g) we measure the evolution of gas to determine the rate of reaction. At the beginnin

Question

3 years ago

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In the reaction 2HgO(s) --> 2Hg(l) + O2(g) we measure the evolution of gas to determine the rate of reaction. At the beginnin

g of the reaction (at 0 minutes), 0.02 L of O2 is present. After 10 minutes the volume of O2 is 0.36 L. What is the rate of reaction? Question 4 options:

Mathematics

1 answer:

djverab [1.8K] · Answer 1 · 2022-05-29T01:59:43+03:00

djverab [1.8K]3 years ago

4 0

Answer:

0.034 L/min

Step-by-step explanation:

The rate of reaction is the volume change (ΔV) divided by the time(t) and divided by the coefficient of the compound in the reaction. The coefficient of O₂ is 1, so:

R = (0.36 - 0.02)/10

R = 0.034 L/min