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Airida [17]
2 years ago
8

Which statements are correct? Check all that apply. One-halfQP = UT One-halfTS = RQ SU = PR SU âÂÄ„ RP UT ⊥ RP.

Mathematics
2 answers:
irina1246 [14]2 years ago
8 0

Answer:

1 and 4

Step-by-step explanation:

Alik [6]2 years ago
6 0

Only option 1 and 4 are true.

Points S, U, and T are the midpoints of the sides of ΔPQR.

ΔSUT is inside of ΔPQR. Points S, U, and T are the midpoints of ΔPQR.

Which statements are correct? Check all that apply.

1.   QP = UT

2.   One-halfTS = RQ

3.   SU = PR

4.   SU ∥ RP

5.   UT ⊥ RP

Given to us,

S, U, and T are the midpoints of the sides of ΔPQR.

Using Triangle Midpoint Theorem, which states that the line segment connecting the midpoints of two sides of a triangle is parallel to the third side and is congruent to one half of the third side.

Therefore, only option 1 and 4 are true.

To know more visit:

brainly.com/question/8943202

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An experiment to investigate the survival time in hours of an electronic component consists of placing the parts in a test cell
mixer [17]

Answer:

a) The sample mean is of 49 and the sample standard deviation is of 11.7.

b) The range of the true mean at 90% confidence level is of 9.62 hours.

c) The prediction interval, at a 90% confidence level, of it's failure time is between 39.38 hours and 58.62 hours.

Step-by-step explanation:

Question a:

Sample mean:

\overline{x} = \frac{34+40+46+49+61+64}{6} = 49

Sample standard deviation:

s = sqrt{\frac{(34-49)^2+(40-49)^2+(46-49)^2+(49-49)^2+(61-49)^2+(64-49)^2}{5}} = 11.7

The sample mean is of 49 and the sample standard deviation is of 11.7.

b)Determine the range of the true mean at 90% confidence level.

We have to find the margin of error of the confidence interval. Since we have the standard deviation for the sample, the t-distribution is used.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 6 - 1 = 5

90% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 5 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.9}{2} = 0.95. So we have T = 2.0.150

The margin of error is:

M = T\frac{s}{\sqrt{n}}

In which s is the standard deviation of the sample and n is the size of the sample. So

M = 2.0150\frac{11.7}{\sqrt{6}} = 9.62

The range of the true mean at 90% confidence level is of 9.62 hours.

(c)If a seventh sample is tested, what is the prediction interval (90% confidence level) of its failure time.

This is the confidence interval, so:

The lower end of the interval is the sample mean subtracted by M. So it is 49 - 9.62 = 39.38 hours.

The upper end of the interval is the sample mean added to M. So it is 49 + 9.62 = 58.62 hours.

The prediction interval, at a 90% confidence level, of it's failure time is between 39.38 hours and 58.62 hours.

4 0
2 years ago
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stich3 [128]

Answer: Falling

Step-by-step explanation:

Once you rearrange this equation into y-intercept form and you get y = -4x-3, you then graph the line and the line appears to be decreasing down.

6 0
3 years ago
What is the solution to this equation?<br> 325 + 12 = 39
Stolb23 [73]

Answer:

there is no solution to it as the equation isn't true (It doesn't make sense)

Step-by-step explanation:

8 0
3 years ago
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Answer:

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A business owes $8000 on a loan. Every month, the business pays 1/2 of the amount remaining on the loan. How much will the busin
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Answer:

125

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