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kotegsom [21]
3 years ago
14

$14,038 is invested, part at 14% and the rest at 12%. If the interest earned from the amount invested at 14% exceeds the interes

t earned from the amount invested at 12% by $984.34, how much is invested at each rate? (Round to two decimal places if necessary.)
Mathematics
1 answer:
Advocard [28]3 years ago
5 0

Answer:

492.99

Step-by-step explanation: x = amount invested at 12%

y = amount invested at 9%

---

x + y = 20287

0.12x = 0.09y + 492.99

---

put the system of linear equations into standard form

---

x + y = 20287

0.12x - 0.09y = 492.99

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Answer:

x = ± \sqrt{2} , x = ± i

Step-by-step explanation:

f(x) = x^{4} - x² - 2

to find the zeros , equate f(x) to zero , that is

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using the substitution u = x² , then

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x = ± \sqrt{2}

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