Let
x--------> the number of dozen of eggs
f(x)-------> the number of eggs
we know that

The domain of the function is the amount of dozens of eggs that Monica can buy
The domain is the interval-------> ![[2,3,4,5,6]](https://tex.z-dn.net/?f=%5B2%2C3%2C4%2C5%2C6%5D)
All integers from
to
, inclusive
The range is the interval-------> ![[27, 39, 51, 63, 75]](https://tex.z-dn.net/?f=%5B27%2C%2039%2C%2051%2C%2063%2C%2075%5D)
therefore
<u>the answer is the option</u>
All integers from
to
, inclusive
N-the number
the product of 8 and the number: 8 × n = 8n
5 less than the 8n: <u>8n - 5</u>
Answer:
90
Step-by-step explanation:
90/10= 9
90/5= 18
No number larger than 90 would work.
Answer:
A. E(x) = 1/n×n(n+1)/2
B. E(x²) = 1/n
Step-by-step explanation:
The n candidates for a job have been ranked 1,2,3....n. Let x be the rank of a randomly selected candidate. Therefore, the PMF of X is given as
P(x) = {1/n, x = 1,2...n}
Therefore,
Expectation of X
E(x) = summation {xP(×)}
= summation {X×1/n}
= 1/n summation{x}
= 1/n×n(n+1)/2
= n+1/2
Thus, E(x) = 1/n×n(n+1)/2
Value of E(x²)
E(x²) = summation {x²P(×)}
= summation{x²×1/n}
= 1/n