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mixer [17]
3 years ago
11

If medium 1 is glass, could medium 2 be zircon? Explain your answer with reference to index of refraction.

Physics
1 answer:
Brrunno [24]3 years ago
5 0

Answer:

So the answer would be no, because the medium 1 value must be greater than the value of medium 2.

Explanation:

The value of n1 must be greater than the value of n2.

Medium 1 - Index of Refraction (n1): 1.52  

Medium 2 - Index of Refraction (n2): 1.92

I think that is correct

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A moving walkway has a speed of .4 m/s to the east. A stationary observer sees a man walking on the walkway with a velocity of 3
SVEN [57.7K]

Explanation:

Vnet = 0.4m/s - 3.0m/s = - 2.6m/s

so the man walks 2.6m/s towards the west

8 0
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Hãy kể tên, kí hiệu, đơn vị một số đại lượng Vật Lý mà em đã học ở lớp 10, 11?
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7 0
3 years ago
How do weathering and erosion differ?
anzhelika [568]

Answer:

weathering breaks down the rocks while erosion moves them away from its original growth

7 0
3 years ago
Read 2 more answers
1. On one of the shelves in your physics lab is displayed an antique telescope. A sign underneath the instrument says that the t
Ira Lisetskai [31]

Answer:

a)  f_{e} = 3,375 cm , b)  f₀ = 77.625 cm

Explanation:

The magnification of a telescope is, to see at the far point of vision (infinity image)

        m = - f₀ /  f_{e}

The length of the tube is

        L = f₀ + f_{e}

a) The focal length of the eyepiece

       L = - m  f_{e} +  f_{e}

       L = f_{e} (1-m)

        f_{e} = L / (1-m)

Let's calculate

        f_{e} = 81.0 / (1 - (-23.0)

        f_{e} = 3,375 cm

b) the focal length of the target

       f₀ = -m  f_{e}

       f₀ = 23 (3.68)

       f₀ = 77.625 cm

8 0
4 years ago
a rocket is launched with a constant acceleration straight up. exactly 4.00 seconds after lift off, a bolt falls off the side of
Papessa [141]

The initial speed of the bolt is not 58.86 m/s.  

Let a be the acceleration of the rocket.  

During the 4 sec lift off, the rocket has reached a height of  

h = (1/2)*a*t^2  

with t=4,  

h = (1/2)*a^16  

h = 8*a  

Its velocity at 4 sec is  

v = t*a  

v = 4*a  

The initial velocity of the bolt is thus 4*a.  

During the 6 sec fall, the bolt has the initial velocity V0=-4*a and it drops a total height of h=8*a. From the equation of motion,  

h = (1/2)*g*t^2 + V0*t  

Substituting h0=8*a, t=6 and V0=-4*a into it,  

8*a = (1/2)*g*36 - 4*a*6  

Solving for a  

a = 5.52 m/s^2

6 0
3 years ago
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