Answer:
0.114 kg or 114 g
Explanation:
From the diagram attaches,
Taking the moment about the fulcrum,
sum of clockwise moment = sum of anticlockwise moment.
Wd = W'd'
Where W = weight of the mass, W' = weight of the meter rule, d = distance of the mass from the fulcrum, d' = distance of the meter rule.
make W' the subject of the equation
W' = Wd/d'................ Equation 1
Given: W = mg = 0.0515(9.8) = 0.5047 N, d = (39.2-16) = 23.2 cm, d' = (49.7-39.2) = 10.5 cm
Substitute these values into equation 1
W' = 0.5047(23.2)/10.5
W' = 1.115 N.
But,
m' = W'/g
m' = 1.115/9.8
m' = 0.114 kg
m' = 114 g
Answer:
The archerfish must spit at a minimum speed of
at an angle of
above the horizontal.
Explanation:
Hi
First of all, we need to find the angle above the horizontal at which the archerfish must spit, as we can see in the attachment this angle is
.
Then we use the formula
, as we clear it for
, we obtain,
, therefore the archerfish must spit at a minimum speed of
at an angle of
above the horizontal.
The potential energy is most often referred to as the "energy at rest" and is dependent on the elevation of an object. This can be calculated through the equation,
E = mgh
where E is the potential energy, m is the mass, g is the acceleration due to gravity, and h is the height. In this item, we are not given with the mass of the cart so we assume it to be m. The force is therefore,
E = m(9.8 m/s²)(0.5 m) = 4.9m
Hence, the potential energy is equal to 4.9m.
Answer:
a
b

Explanation:
From the question we are told that
The pressure of the manometer when there is no gas flow is 
The level of mercury is 
The drop in the mercury level at the visible arm is 
Generally when there is no gas flow the pressure of the manometer is equal to the gauge pressure which is mathematically represented as

Here
is the density of mercury with value 
and
is the difference in the level of gas in arm one and two
So


Generally the height of the mercury at the arm connected to the pipe is mathematically represented as

=> 
Generally from manometry principle we have that
![P_G + \rho * g * d - \rho * g * [h - (h_m + d)] = 0](https://tex.z-dn.net/?f=P_G%20%2B%20%5Crho%20%2A%20g%20%20%2A%20d%20%20%20-%20%20%5Crho%20%2A%20%20g%20%20%2A%20%5Bh%20-%20%28h_m%20%2B%20d%29%5D%20%3D%200)
Here
is the pressure of the gas
![P_G +13.6 *10^{3} * 9.8 * 0.039 - 13.6 *10^{3} * 9.8 * [0.950 - (0.148 + 0.039)] = 0](https://tex.z-dn.net/?f=P_G%20%2B13.6%20%2A10%5E%7B3%7D%20%2A%209.8%20%20%2A%200.039%20%20%20%20-%20%2013.6%20%2A10%5E%7B3%7D%20%20%2A%20%209.8%20%20%2A%20%5B0.950%20-%20%280.148%20%2B%200.039%29%5D%20%3D%200)

converting to psig
This is a true and false question correct or did you accidentally put two truths ??