Statement A is true. R4 is not part of the circuit since it has one terminal not connected. The other resistors are in series, so the same current flows through them. Hence they will dissipate equal power.
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Answer:
#include <iostream>
using namespace std;
void printmultiples(int n) //function to print first five multiples between 3168 and 376020
{
int a =3168,c=1;
cout<<"First five multiples of "<<n<<" are : ";
while(a%n!=0 && a<=376020) //finding first mutiple of n after 3168.
{
a++;
}
while(c<6)//printing multiples.
{
cout<<a<<" ";
a+=n;
c++;
}
cout<<endl;
}
int main() {
int t,n;
cin>>t;//How many times you want to check.
while(t--)
{
cin>>n;
printmultiples(n);//function call..
}
return 0;
}
Input:-
3
15
43
273
Output:-
First five multiples of 15 are : 3180 3195 3210 3225 3240
First five multiples of 43 are : 3182 3225 3268 3311 3354
First five multiples of 273 are : 3276 3549 3822 4095 4368
Explanation:
I have used a function to find the first five multiples of the of the numbers.The program can find the first five multiples of any integer between 3168 and 376020.In the function I have used while loop.First while loop is to find the first multiple of the integer n passed as an argument in the function.Then the next loop prints the first five multiples by just adding n to the first multiple.
In the main function t is for the number of times you want to print the multiples.In our case it is 3 Then input the integers whose multiples you want to find.
<span>Larry recently viewed an auction listing on a website. as a result, his computer executed code that popped up a window that asked for his password. The type of attack larry had likely encountered is the </span><span>Cross-site scripting (XSS).</span>
Music = (“rap”, “hip hop”, “gospel”)
Country = (“country”,) #make sure that comma is outside of quotes
New_music = music + Country
print(New_music)
#var can be whatever you want
output:
(“rap”, “hip hop”, “gospel”, “country”)