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2 years ago

Find the solution to the equation -2(x + 5) = -16. x =

Mathematics

2 answers:

Radda [10]2 years ago

8 0

Answer:

x = 5/7 = 0.714

Step-by-step explanation:

BaLLatris [955]2 years ago

7 0

Answer is 5/7 = 0.714

See photo

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Anton [14]

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2 years ago

Solve the following equation for A. Be sure to take into account whether a letter is

Sati [7]

Answer:

4/a

Step-by-step explanation:

8 0

2 years ago

Math Test Helpppppp!!!!!!!!

soldier1979 [14.2K]

Simple problem:

When simplifying 3(x-6) they subtracted 3 instead of multiplied by 3.
3(x-6) should be 3x-18.
Now when you simplify:
3x-18+4x+12-6x
Which is x -6 =0
Or x =6

3 0

2 years ago

Choose the best coordinate system to find the volume of the portion of the solid sphere rho <_4 that lies between the cones φ

MrRissso [65]

Answer:

So, the volume is:

$\boxed{V=\frac{128\sqrt{2}\pi}{3}}$

Step-by-step explanation:

We get the limits of integration:

$R=\left\lbrace(\rho, \varphi, \theta):\, 0\leq \rho \leq 4,\, \frac{\pi}{4}\leq \varphi\leq \frac{3\pi}{4},\, 0\leq \theta \leq 2\pi\right\rbrace$

We use the spherical coordinates and we calculate a triple integral:

$V=\int_0^{2\pi}\int_{\frac{\pi}{4}}^{\frac{3\pi}{4}}\int_0^4 \rho^2 \sin \varphi \, d\rho\, d\varphi\, d\theta\\\\V=\int_0^{2\pi}\int_{\frac{\pi}{4}}^{\frac{3\pi}{4}} \sin \varphi \left[\frac{\rho^3}{3}\right]_0^4\, d\varphi\, d\theta\\\\V=\int_0^{2\pi}\int_{\frac{\pi}{4}}^{\frac{3\pi}{4}} \sin \varphi \cdot \frac{64}{3} \, d\varphi\, d\theta\\\\V=\frac{64}{3} \int_0^{2\pi} [-\cos \varphi]_{\frac{\pi}{4}}^{\frac{3\pi}{4}} \, d\theta\\\\V=\frac{64}{3} \int_0^{2\pi} \sqrt{2} \, d\theta\\\\$

we get:

$V=\frac{64}{3} \int_0^{2\pi} \sqrt{2} \, d\theta\\\\V=\frac{64\sqrt{2}}{3}\cdot[\theta]_0^{2\pi}\\\\V=\frac{128\sqrt{2}\pi}{3}$

So, the volume is:

$\boxed{V=\frac{128\sqrt{2}\pi}{3}}$

4 0

3 years ago

One of the corners of a rectangle is shown.

tensa zangetsu [6.8K]

Answer:

70 degrees

Step-by-step explanation:

rectange angle total = 360

1 corner = 90

90-20 = 70

8 0

2 years ago