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motikmotik
3 years ago
14

A linear function has a slope of -7/9 and a y-intercept of 3. How does this function compare to the linear function that is repr

esented by the equation y+11=-7/9(x-18)
Mathematics
2 answers:
sergij07 [2.7K]3 years ago
8 0

Answer:

A

Step-by-step explanation:

it has the same slope and the same y-intercept

Dmitriy789 [7]3 years ago
4 0
The answer is that they're equal, one is just in point-slope form and the other is in slope-intercept form
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51. Jonathan is selling vintage albums to a rare music
Doss [256]
The answer is D.$27.50
6 0
3 years ago
ITO
Setler [38]

Using the speed - distance relationship, the time left before the appointed time is 27 minutes.

<u>Recall</u><u> </u><u>:</u>

  • Distance = speed × time

  • Let time = t

<u>At</u><u> </u><u>10mph</u><u> </u><u>:</u>

  • Distance = 10 × (t + 3) = 10t + 30 - - - (1)

<u>At</u><u> </u><u>12</u><u> </u><u>mph</u><u> </u><u>:</u>

  • Distance = 12 × (t - 2) = 12t - 24 - - - - (2)

<em>Equate</em><em> </em><em>(</em><em>1</em><em>)</em><em> </em><em>and</em><em> </em><em>(</em><em>2</em><em>)</em><em> </em><em>:</em>

10t + 30 = 12t - 24

<em>Collect</em><em> </em><em>like</em><em> </em><em>terms</em><em> </em>

10t - 12t = - 24 - 30

-2t = - 54

<em>Divide</em><em> </em><em>both</em><em> </em><em>sides</em><em> </em><em>by</em><em> </em><em>-</em><em> </em><em>2</em>

t = 54 / 2

t = 27

Hence, the time left before the appointed time is 27 minutes.

Learn more : brainly.com/question/25669152

8 0
2 years ago
Read 2 more answers
Please help, the picture shows what the question is, thanks!
maksim [4K]

Answer:

V≈2412.74

Step-by-step explanation:

5 0
3 years ago
((-2^2)(-1^-3))•((-2^-3)(-1^5))^-2
Vitek1552 [10]

Answer:

  256

Step-by-step explanation:

A calculator works well for this.

_____

None of the minus signs are subject to the exponents (because they are not in parentheses, as (-1)^5, for example. Since there are an even number of them in the product, their product is +1 and they can be ignored.

1 to any power is still 1, so the factors (1^n) can be ignored.

After you ignore all of the things that can be ignored, your problem simplifies to ...

  (2^2)(2^-3)^-2

The rules of exponents applicable to this are ...

  (a^b)^c = a^(b·c)

  (a^b)(a^c) = a^(b+c)

Then your product simplifies to ...

  (2^2)(2^((-3)(-2)) = (2^2)(2^6)

  = 2^(2+6)

  = 2^8 = 256

3 0
3 years ago
To what subsets does -17 belong
Nikolay [14]
Rational number, negative, integer
5 0
3 years ago
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