The equation of the quadratic function is f(x) = x²+ 2/3x - 1/9
<h3>How to determine the quadratic equation?</h3>From the question, the given parameters are:
Roots = (-1 - √2)/3 and (-1 + √2)/3
The quadratic equation is then calculated as
f(x) = The products of (x - roots)
Substitute the known values in the above equation
So, we have the following equation
This gives
Evaluate the products
Evaluate the like terms
So, we have
f(x) = x²+ 2/3x - 1/9
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The equation of line that passes through the points (-3,-1) and
(-6,3) is:
Step-by-step explanation:
Given points are:
(-3,-1) =(x1,y1)
(-6,3)=(x2,y2)
The slope-intercept form of equation of line is:
We have to find the slope first
Putting the value of slope in the slope intercept form
To find the value of b, putting the point (-3,-1) in the equation
Putting the values of b and m
The equation of line that passes through the points (-3,-1) and
(-6,3) is:
Keywords: Equation of line, slope intercept form
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