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2 years ago

What is the perimeter of a triangle with sides 12 inches, 9 inches, and 15 inches

1 answer:

6 0

The perimeter will be 12+9+15 = 36 inches

bc. for you get the perimeter of a triangle just you need assuming the length of sides

hope helped

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3 years ago

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Need help with this geometry assignment due soon smart people and mark Brainly

skad [1K]

Answer:

1. a + b + c = 180

2. b + d = 180

3. d = a + c

Step-by-step explanation:

1. a + b + c = 180:

Angles in a triangle add up to 180

2. b + d = 180:

Angles in a straight line equal 180 because they are supplementary angles

3. d = a + c:

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3 years ago

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Please find x and y <br><br>x=y-4 and -2x+3y=6

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Answer:

x=y-4 is x=y-4

y=2+ 2x/2

Step-by-step explanation:

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2 years ago

An exam has two probability problems, 1 and 2. If 37% of the students solved problem 1 and 12% of the students solved both probl

Zanzabum

Answer:

about 32%

Step-by-step explanation:

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3 years ago

Solve.

Nikitich [7]

The answer is C: $10\text{ }^1/_2$ . Here are the details:

$\text{Equation:}\\ 6\text{ }^1/_3+10\text{ }^1/_2\stackrel{?}{=}26\text{ }^1/_6\\ \\ \text{Start with the integers.}\\ 6+10=16\stackrel{?}{=}26\text{ }^1/_6\\ \\ \text{...then with the fractions, but rewrite them first to make it easier.}\\ ^1/_3+\text{ }^1/_2\stackrel{\text{rewrite}}{\to}\text{ }^2/_6+\text{ }^3/_6=\text{ }^5/_6\stackrel{?}{=}26\text{ }^1/_6\\
\\
\text{Add 'em up!}\\
16\text{ }^5/_6$

$\text{Equation:}\\
16\text{ }^5/_6+3\text{ }^5/_6\stackrel{?}{=}26\text{ }^1/_6\\
\\
\text{Start with the integers.}\\
16+3=19\stackrel{?}{=}26\text{ }^1/_6\\
\\
\text{...then with the fractions, but rewrite them first to make it easier.}\\
^5/_6+\text{ }^5/_6=\text{ }^{10}/_6\stackrel{\text{rewrite}}{\to}\text{ }^5/_3\stackrel{\text{rewrite}}{\to}1\text{ }^2/_3\stackrel{?}{=}26\text{ }^1/_6\\
\\
\text{Add 'em up!}\\
20\text{ }^2/_3$

$\text{Last equation:}\\ 20\text{ }^2/_3+5\text{ }^1/_2\stackrel{?}{=}26\text{ }^1/_6\\ \\ \text{Start with the integers.}\\ 20+5=25\stackrel{?}{=}26\text{ }^1/_6\\ \\ \text{...then with the fractions, but rewrite them first to make it easier.}\\ ^2/_3+\text{ }^1/_2\stackrel{\text{rewrite}}{\to}\text{ }^4/_6+\text{ }^3/_6=\text{ }^7/_6\stackrel{\text{rewrite}}{\to}1\text{ }^1/_6\stackrel{?}{=}26\text{ }^1/_6\\
\\
\text{Add the integer and fraction together.}\\
25+1\text{ }^1/_6\stackrel{?}{=}26\text{ }^1/_6$

$26\text{ }^1/_6\stackrel{\checkmark}{=}26\text{ }^1/_6$

5 0

2 years ago