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devlian [24]
3 years ago
15

I need to know the length

Mathematics
2 answers:
seropon [69]3 years ago
6 0
The length is 15. Hope this helps. :)
Katarina [22]3 years ago
4 0
The lenght is 15 hope this will help you
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Wich equation gives the number of 1/3 inches that are in 5/6 inches
lara31 [8.8K]

Hello from MrBillDoesMath!

Answer:

(1/3) x = (5/6)


Discussion:

I think you are asking for this equation:

(1/3) x = (5/6) =>            multiply both sides by 3

(1/3) 3 x = (5/6) 3 =>      as (1/3) *3 = 1

x = 5*3/6

x= 15/6

x = 5/2 = 2.5

Thank you,

MrB

6 0
3 years ago
Mrs. Jackson put a total of $10,000 into two accounts one account earns 6% simple annual interest the other account earns 6.5% s
kozerog [31]

Answer:

The money invested in account at 6 % rate is $ 9230.77

The money invested in account at 6.5 % rate is $ 769.23

Step-by-step explanation:

Given as :

The total amount saves in two account = $ 10,000

The two rate of interest are 6 % and 6.5 % at simple interest

The interest earn at 6 % rate = $ 632

The interest earn at 6.5 % ate = $ 50

Now, Let The amount deposit at 6 % rate = $ x

And The amount deposit at 6.5 % rate = $ 10,000 - $ x

<u>From Simple Interest method</u>

Simple Interest = \dfrac{\textrm principal \times \textrm Rate\times \textrm time}{100}

or, At 6.5 % rate

$ 50 =  \dfrac{\textrm (10,000 - x ) \times \textrm 6.5\times \textrm 1}{100}

or, 10000 - x =  \frac{5000}{6.5}

Or, 10000 - x = 769.23

∴  x = 10000 - 769.23

I.e x = $ 9230.77

So , At 6.5 % the amount deposit = 10,000 - 9230.77 = $ 769.23

So, At 6 % The amount deposit  = $ 9230.77

Hence The money invested in account at 6 % rate is $ 9230.77

And  The money invested in account at 6.5 % rate is $ 769.23 Answer

7 0
4 years ago
The length to width ratio of a wide-screen tv is 16:9. if a tv is 30 inches long, how wide is it?
bija089 [108]
It is about 16.9 inches wide
7 0
3 years ago
Read 2 more answers
Can someone help me?
SOVA2 [1]

Answer:

what does the picture say?

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Using these complex zeros (1,1,-1/2,2+i,2-i) factor f(x)=-2x^5 +11x^4 -22x^3 +14x^2 +4x -5
Marianna [84]
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\bf (x^2-2x+1)(2x+1)~[(x-2)^2-(i)^2]&#10;\\\\\\&#10;(x^2-2x+1)(2x+1)~[(x^2-4x+4)-(-1)]&#10;\\\\\\&#10;(x^2-2x+1)(2x+1)~[(x^2-4x+4)+1]&#10;\\\\\\&#10;(x^2-2x+1)(2x+1)~[x^2-4x+5]&#10;\\\\\\&#10;(x^2-2x+1)(2x+1)(x^2-4x+5)

of course, you can always use  (x-1)(x-1)(2x+1)(x²-4x+5)  as well.
7 0
3 years ago
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