Answer:
DNA template sequence:
5' TGACCAAGT 3'
RNA antisense sequence: 3' UGACCAAGU 5'
>>> RNA sense sequence (transcript) : UGAACCAGU
Explanation:
In the DNA molecule, four types of nitrogenous bases are found: cytosine (C), and guanine (G), adenine (A) and thymine (T). In DNA the bases pair up with each other in the following ways: A pairs with T by two hydrogen bonds, while C pairs with G by three hydrogen bonds. In RNA (i.e., transcript sequence), T is replaced by uracil (U). Moreover, the RNA nucleotide sequence is read in the direction 5' to 3'.
Answer:
they ensure valid results
Answer:
Reading graphs: The variable plotted on the x-axis is year while the two variables plotted on y-axis are both wolves and moose.
Interpreting variables: The population of moose rose from 800 to 1550 between 1965-1972 while the population of wolves rose from 24 to 43 between 1973-1976.
inferring: The change in population of moose might cause a change in wolves population as a result of the feeding pattern of wolves, perhaps the contest between them was affected by availability of another prey which allows the predator (wolves) to feed on another prey, hence increasing the population of moose.
Conclusion: The dip in population of moose between 1974 and 1981 could be attributed to voracious feeding pattern the predator (wolves) had on the prey (moose) which inturns allows the dip in population during the above mentioned years.
Predicting: If there is a disease infection in wolves, then there would be an increase in the population of moose the next year as a result of disruption in the predator-prey contest, hence; allows one to be more populated the following year.
Explanation:
From the above assertions, it could be deduced that only when the feeding pattern of the predator (wolves) changes then the population of the prey would either be reduced or increased.
I would go with lipids:) hope it helps
