Answer:
Hello!!
The sum of 3 constructive numbers is 126. The three constructive numbers are...

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Since the degree of this polynomial is 5, there will be 5 possible zeros. To find the possible rational 0s, use the rational root theorem (p/q). P is the last, non x value, which here it is the four on the end. The q is the leading coefficient, which is also q. Next, find all of the factors of q and p, which since they are both 4, are ±1, ±2, and ±4. Next do all possible values of p/q, which are ±1, ±2, ±4, ±1/2, and ±1/4. These are all your possible rational zeros. complex 0s only come in pairs, so the maximum there can be is 4 complex zeros, meaning there is at least one rational, real 0. (i graphed it it is -1/2, so all others must be rational or imaginary)
Answer:
B Probably shouldn't trust me
Step-by-step explanation:
I'm guessing 10 days, since you lost a bit more than half of the workers, and it would take longer for the job to get done.
Answer:
Equivalent fractions
Step-by-step explanation: