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3 years ago

How do i explain Associative Property of Multiplication

Mathematics

2 answers:

likoan [24]3 years ago

6 0

Answer:

The associative property is a math rule that says that the way in which factors are grouped in a multiplication problem does not change the product.

Go to Khan Academy for more.

Step-by-step explanation:

N76 [4]3 years ago

6 0

Answer:

The way in which factors are grouped in a multiplication problem, does not change the product.

Step-by-step explanation:

my brain ;p

You might be interested in

Which of the following is not equal to sin⁡(-230°)?

xenn [34]

From trigonometry we know that:

if $sin(\theta)=sin(\alpha)$

then, $\theta=n\pi+(-1)^n\alpha$ (where $n$ is an integer)

This can be rewritten in degrees as:

$\theta=n(180^{\circ})+(-1)^n\alpha$ .............(Equation 1)

Now, in our case, $\alpha=-230^{\circ}$

Therefore, (Equation 1) can be written as:

$\theta=n(180^{\circ})+(-1)^n(-230^{\circ})$ ..........(Equation 2)

Now, to find the correct options all that we have to do is replace n by relevant integers and find the values of $\theta$ that match.

For n=2, (Equation 2) gives us: $\theta=2\times 180^{\circ}+(-1)^2(-230^{\circ})=360^{\circ}-230^{\circ}=130^{\circ}$ .

Thus, $sin(230^{\circ})=sin(130^{\circ})$

Now, we know that: $-sin(-50^{\circ})=sin(50^{\circ})$

Let n=-1, then:

$\theta=(-1)\times 180^{\circ}+(-1)^{-1}(-230^{\circ})=-180^{\circ}+230^{\circ}=50^{\circ}$

Thus, $sin(-230^{\circ})=-sin(-50^{\circ})$

Likewise, $sin(-230^{\circ})=sin(50^{\circ})$

Only the last option $sin(-50^{\circ})$ will never match $sin(-230^{\circ})$ because no integral value of $n$ will ever give $\theta=-50^{\circ}$

Thus the last option is the correct option.

3 0

3 years ago

Read 2 more answers

HELP!!!!In 2004, school lunch Rockwell high school was $2.20.In 2009 the costs increased to $3.25. Find the annual rate of chang

arsen [322]

Answer:

$0.21 per year

Step-by-step explanation:

$0.21 times 5 years equals $1.05

So its $0.21

5 0

3 years ago

Given the inequality below: 3x-y>4 Which is the graph of the solution set?

OLga [1]

Answer:

A shaded region below a dashed line (y <3x-4)

Step-by-step explanation:

For linear inequalities, we have shaded regions below or above a dashed or solid or continuous line represented by an inequality.

Their graphs are called region graphs. Those regions are only enclosed ones if before the sign of inequality it is included both variables. Like x²+y²<1, |x+y|<1, etc.

In this case what we have here is an open region, as the graph below shows.

3x-y>4 =-y>4-3x∴y<3x-4

Setting a value for x

3x-4=0

3x=4

3x/3=4/3

x=4/3 (slope)

(4/3,0)

6 0

3 years ago

Divide using long division. Checky (x3+ 3x2 + x - 9) = (x - 1)

Montano1993 [528]

Answer:

x squared plus 2x minus 1.

Step-by-step explanation:

x3+3x2+x-9 is in the division "house" and x-1 is on the outside. xsquare times x equals x cubed. and x square times negative 1 equals -x squsre. put x square on top of the roof. change the signs. the x cubed cancels out. and bring down 2x square from subtracting 3x square and -x square and bring down the x-9. Put 2x on top of the roof too and 2x times x equals 2x square and multiply by -1. U will have 2x square -2x square and -2x plus x which equals -1x cuz the 2x square cancels out. bring down the -9. Now i have -1x-9. Multiply by -1 and put -1 on the roof. -1x+1x cancels out. and -1 times -1 equals positive 1. So -9+1=8. U van do any further cause as soon as the last number is at the end of the roof and u cant go further, ur done dividing. so the answer is x square+2x-1/×-1 +8 as the remainder. hope i helped

6 0

3 years ago

A. The point-slope form of the equation of a line is y ? y1 = m(x ? x1), where m is the slope and (x1, y1) is a point on the lin

Rudiy27

Answer:

$y - 5 = -2(x-6)$

Negative reciprocal gives you the perpendicular slope so negative reciprocal of 1/2 is -2.

Then apply point-slope form.

B. The answer is x = 6.

The midpoint of JK is

$\left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right) = \left( \frac{8+ 4}{2}, \frac{4 + 4}{2} \right) = \left(6,4\right)$

The line that goes through JK is just a horizontal line $y = 4$ because the y-coordinate does not change. So its perpendicular bisector is the vertical line that goes through the x-coordinate of the midpoint, that is, $x = 6$ .

8 0

3 years ago