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2 years ago

What is the area of the real object that the scale drawing models?

Mathematics

1 answer:

Kruka [31]2 years ago

7 0

Answer:

HOPE THIS HELPS!!

Step-by-step explanation:

YOU could find it by doing these steps:

Atual Area = �� square units.

Scale Drawing Area = �� square units.

Value of the Ratio of the Scale Drawing Area to the Actual Area:

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Four-fifths of a number decreased by two is eighteen

hodyreva [135]

Pls mark me brainiless

(4/5)(x - 2) = 18
4(x - 2) = 90
4x = 98
x = 24 1/2

5 0

3 years ago

Jason and Alison are hiking in the woods when they spot a rare owl in a tree. Jason stops and measures an angle of elevation of

Shalnov [3]

Answer:

$Owl= 67.14ft$

Step-by-step explanation:

<em>See comment for complete question.</em>

The given information is represented in the attached figure.

First convert 22°8'6'' and 30° 40’ 30” to degrees

$22^{\circ} 8'6'' = 22 + \frac{8}{60} + \frac{6}{3600}$

$22^{\circ} 8'6'' = 22.135^{\circ}$

$30^{\circ} 40'30'' = 30 + \frac{40}{60} + \frac{30}{3600}$

$30^{\circ} 40'30'' = 30.675^{\circ}$

Considering Jason's position:

$tan(22.135^{\circ}) = \frac{H}{x + 48}$

Where x = distance between the tree and Alison

Make H the subject

$H = (x + 48)tan(22.135^{\circ})$

Considering Alison's position

$tan(30.675^{\circ}) = \frac{H}{x}$

Make H the subject

$H = xtan(30.675^{\circ})$

$H = H$

$(x + 48)tan(22.135^{\circ}) = xtan(30.675^{\circ})$

$(x + 48) *0.4068 = x* 0.5932$

Open bracket

$x *0.4068 + 48 *0.4068 = 0.5932x$

$0.4068x + 19.5264 = 0.5932x$

Collect Like Terms

$-0.5932x+0.4068x = -19.5264$

$-0.1864x = -19.5264$

$0.1864x = 19.5264$

Make x the subject

$x = \frac{19.5264}{0.1864}$

$x = 104.76$

Substitute 104.76 for x in $H = xtan(30.675^{\circ})$

$H = 104.76 * tan(30.675^{\circ})$

$H = 104.76 * 0.5932$

$H = 62.14$

The above represents the height of the tree.

The height of the owl is:

$Owl= H + 5$

$Owl= 62.14 + 5$

$Owl= 67.14ft$

7 0

2 years ago

A body and tackle with a velocity ratio of 5 is used to raise a mass of 50kg through a vertical distance of 20n at a steady rate

matrenka [14]

a. Distance moved by effort = 1 meter

b. Work done by effort = 80 Joules

c. Losses in energy = 18 Joules

<h3>How to determine the parameters</h3>

a. Note that velocity ratio is defined as the ratio of a distance through which any part of a machine moves to the distance moved by its parts

Velocity ratio = distance moved by the effort/distance moved by the body

Where velocity ratio = 5

vertical distance = 20cm

Distance moved by effort = 5 × 0. 20 = 1 meter

b. Formula for work done is given as ;

Work done = Effort × distance moved by effort

Work done = 80 × 1

Work done = 80 Newtons

c. First, let's find the work output

Work output = m g h

Work output = 50 × 9.8 × 0. 20

Work output = 98 Joules

Losses in energy = Work output - work done

Losses in energy = 98 - 80

Losses in energy = 18 Joules

Learn more about work done here:

brainly.com/question/25573309

#SPJ1

7 0

2 years ago

Simplest form of ratio 25g:3kg

erica [24]

Answer:

look at the picture.

Step-by-step explanation:

look at the picture.

8 0

1 year ago

Zak has a bag of cherries. He gave away 18 cherries to tim and 18 cherries to janet. Now he has 25 cherries. H ow many cherries

Vlada [557]

Answer: he had 68 cherries in the start

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers