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The total moment of inertia of the two disks will be I = 2.375 × 10-³ Kgm² welded together to form one unit.
<h3>What is moment of inertia?</h3>
Moment of inertia is the quantity expressing a body's tendency to resist angular acceleration, which is the sum of the products of the mass of each particle in the body with the square of its distance from the axis of rotation.
Using the formulas to calculate the moment of inertia of a solid cylinder:
I = ½MR²
Where;
I = moment (kgm²)
M = mass of object (Kg)
R = radius of object (m)
Total moment of inertia of the two disks is expressed as: I = I(1) + I(2)
That is;
I = ½M1R1 + ½M2R2
According to the provided information;
R1 = 2.50cm = 0.025m
M1 = 0.800kg
R2 = 5.00cm = 0.05m
M2 = 1.70kg
I = (½ × 0.800 × 0.025²) + (½ × 0.05² × 1.70)
I = (½ × 0.0005) + (½ × 0.00425)
I = (0.00025) + (0.002125)
I = 0.002375
I = 2.375 × 10-³ Kgm²
Hence The total moment of inertia of the two disks will be I = 2.375 × 10-³ Kgm² welded together to form one unit.
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Answer and Step-by-step explanation:
a.)x^2 and y^2 are always greater than zero.(assuming real x and y).
=>x^2<=x^2+y^2
=>|x|(x^2)<=|x|(x^2+y^2)
=>|x^3|<=|x|(x^2+y^2)
b. similarly, |y^3|<=|y|(x^2+y^2)
=>|f(x,y)|=|x^3+y^3|/(x^2+y^2)=|x|+|y|
c. let h is very small number (close to zero but positive)
lim (x,y)-> (0,0) f(x,y)=(x^3+y^3)/(x^2+y^2)
putting x=h and y=h and approaching h->0
lim h->0 f(h)=2h=0
There is another explanation attached below
Answer:b
Step-by-step explanation:
Answer:
16
Step-by-step explanation:
4*4
