We know that :
If f(x) and g(x) are Two Functions Defined under same Domain, then Composite Function : (f o g)(x) = f(g(x))
Given : f(x) = 
and g(x) = 
⇒ (f o g)(x) = f(g(x))
⇒ 
⇒ 
1st Option is the Answer
Answer:
"The attendance increased by an average of 25 people per game from game 2 to game 5"
Step-by-step explanation:
2nd game had attendance of 680
5th game had attendance of 755
THe increase in number is:
755 - 680 = 75 people
From 2nd to 5th, it is 3 games, so to find PER GAME attendance increase, we divide the increase by number of games. That is:
75/3 = 25
Hence,
<u>"The attendance increased by an average of 25 people per game from game 2 to game 5"</u>
Answer:
18/3
Step-by-step explanation:
6x3=18
9514 1404 393
Answer:
a) average rate = (total distance)/(total time)
b) Rave = 2·R1·R2/(R1 +R2)
c) cheetah's average rate ≈ 50.91 mph
Step-by-step explanation:
a) Let AB represent the distance from A to B. Let t1 and t2 represent the travel times (in hours) on leg1 and leg2 of the trip, respectively. Then the distances traveled are...
First leg distance: AB = 70·t1 ⇒ t1 = AB/70
Second leg distance: AB = 40·t2 ⇒ t2 = AB/40
The average rate is the ratio of total distance to total time:
average rate = (AB +AB)/(t1 +t2)
average rate = 2AB/(AB/70 +AB/40) = 2/(1/70 +1/40) = 2(40)(70)/(70+40)
average rate = 560/11 = 50 10/11 . . . mph
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No equations are given, so we cannot compare what we wrote with the given equations. In each step of the solution, we have used the rules of algebra and equality.
b) For two rates over the same distance (as above), the average is their harmonic mean:
average rate = 2r1·r2/(r1+r2)
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c) The cheetah's average rate was 50 10/11 mph ≈ 50.91 mph.
