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andreyandreev [35.5K]
3 years ago
8

Give the Domain And Range of the function.

Mathematics
1 answer:
Verizon [17]3 years ago
3 0

Answer:

The last one

Step-by-step explanation:

Domain is on the x - axis, so it starts and stops on 1 and 6 and all the other symbols mean that x could be 1, 6, or anything in between. Range is on the y - axis, so the highest point is seven and the lowest is one. Y could be 1, 7, or anything in between.

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HELP ME PLEASE, I NEED THIS DONE LIKE RIGHT NOW
mixer [17]

Answer:

Cos R and sin N

Step-by-step explanation:

5 0
3 years ago
the slope-intercept form of an equation of the line perpendicular to the graph of x – 3y = 5 and passing through (0, 6).
Leona [35]

Answer:

y = - 3x + 6

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Rearrange x - 3y = 5 into this form

Subtract x from both sides

- 3y = - x + 5 ( divide all terms by - 3 )

y = \frac{1}{3} x - \frac{5}{3}  ← in slope- intercept form

with slope m = \frac{1}{3}

Given a line with slope m then the slope of a line perpendicular to it is

m_{perpendicular} = - \frac{1}{m} = - \frac{1}{\frac{1}{3} } = - 3

Note the line crosses the y- axis at (0, 6) ⇒ c = 6

y = - 3x + 6 ← equation of perpendicular line

3 0
3 years ago
Help I’m on a time limit
lys-0071 [83]

Answer:

I think everything you have selected already is correct

Step-by-step explanation:

triangle FGK is congruent to triangle FJK by the SSA Theorem

Angle GKH is congruent to JKH since they are apart of two triangles that are known to be congruent by the SSA Theorem

Angle GFH is congruent to JFH because they are on triangles that are congruent by the SSS Theorem

Then line FG and line KG cannot be proven to be congruent since they are of no correlation to each other

<em>I hope this helps, sorry if I am incorrect</em>

8 0
3 years ago
Need help answering this algebra nation question!
My name is Ann [436]

Answer:

Option 1, 2 and 4

Step-by-step explanation:

3x-4y-8= 12

3x-4y= 12+8 (bring constants to 1 side)

3x-4y= 20 (simplify)

For a point to be a solution of the above equation, substitute the x and y coordinates into 3x-4y and see if it equals to 20.

Option 1: (0, -5)

3(0)-4(-5)= 20

This is correct

2) (4, -2)

3(4)-4(-2)=20

This is correct

3) (8,2)

3(8)-4(2)= 16

This is incorrect.

4) (-16, -17)

3(-16)-4(-17)= 20

This is correct.

5) (-1, -8)

3(-1)-4(-8)= 29

This is incorrect.

6) (-40, -34)

3(-40)-4(-34)= 16

This is incorrect.

3 0
3 years ago
Use elimination to solve<br> 2x+3y=4<br> 4x+6y=-5
zvonat [6]
There is no solution to the problem because it is parallel.
8 0
3 years ago
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