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yawa3891 [41]
2 years ago
10

Please help me!! I’m bad at math!!

Mathematics
2 answers:
tatyana61 [14]2 years ago
5 0

Answer:

50.24

-

And, you're not bad at math! You goot this correct! :)

Step-by-step explanation:

c=25.12

we can use this to find the raidus!

-

plug it back into the circumference formula first.

c=(pi)(d)

25.12=3.14*d

divide both sides by 3.14!

d=8 but we need the radius, so we just divide by 2. 8/2 = 4. so the raidus is 4!

-

now we plug it into the area of a circle formula.

π · r2

3.14 * 4^2

3.14*16

50.24

mr Goodwill [35]2 years ago
5 0
50.24 will be your correct answer.
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2 years ago
Put the differential equation 9ty+ety′=yt2+81 into the form y′+p(t)y=g(t) and find p(t) and g(t). p(t)= help (formulas) g(t)= he
alexgriva [62]

Answer:

p(t) = \frac{9t^{3} + 729t  - 1}{e^{t}(t^{2} + 81) }

g(t) = 0

And

The differential equation 9ty + e^{t}y' = \frac{y}{t^{2} + 81 } is  linear and homogeneous

Step-by-step explanation:

Given that,

The differential equation is -

9ty + e^{t}y' = \frac{y}{t^{2} + 81 }

e^{t}y' + (9t - \frac{1}{t^{2} + 81 } )y = 0\\e^{t}y' + (\frac{9t(t^{2} + 81 ) - 1}{t^{2} + 81 } )y = 0\\e^{t}y' + (\frac{9t^{3} + 729t  - 1}{t^{2} + 81 } )y = 0\\y' + [\frac{9t^{3} + 729t  - 1}{e^{t}(t^{2} + 81) } ]y = 0

By comparing with y′+p(t)y=g(t), we get

p(t) = \frac{9t^{3} + 729t  - 1}{e^{t}(t^{2} + 81) }

g(t) = 0

And

The differential equation 9ty + e^{t}y' = \frac{y}{t^{2} + 81 } is  linear and homogeneous.

6 0
2 years ago
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PtichkaEL [24]
<h3><u>Answer:</u></h3>

Option: D

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<h3><u>Step-by-step explanation:</u></h3>

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We know that when a parent function f(x) is replaced by f(kx) then either the graph is stretched horizontally or shrinked horizontally.

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3 0
3 years ago
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