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elena-s [515]
2 years ago
12

A tin of biscuits contains shortbread and choc-chip biscuits in the ratio 2:3 . The tin contains 80 biscuits. How many short-bre

ad biscuits are there in the tin?
Mathematics
1 answer:
Aleksandr [31]2 years ago
5 0

Answer:

32

Step-by-step explanation:

There are 80 biscuits inside the tin.

Also, they said that those biscuits are in the ratio

Short bread    :      Choc - chip

          2          :        3

Altogether there are 5 shares ( 2 + 3)

And now you can divide 80 by 5 to find how many biscuits contain per a share.

80 ÷ 5 = 16

In the question, they asked us to to find the number of short biscuits inside the tin.

Let us find that.

There are 2 shares for short bread biscuits.

So,

Number of short biscuits ⇒ 2 × 16

                                         ⇒ 32

Hope this helps you :-)

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The histogram shows the duration, in minutes, of movies in theaters.
neonofarm [45]

The <em>correct answer</em> is:

The median is less than the mean.

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m_a_m_a [10]

Answer:

a) H0 : u = 28.5%

H1 : u < 28.5%

b) critical value = - 1.645

c) test statistic Z= - 1.41

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e) There is not enough evidence to support the professor's claim.

Step-by-step explanation:

Given:

P = 28.5% ≈ 0.285

X = 210

n = 800

p' = \frac{X}{n} = \frac{210}{800} = 0.2625

Level of significance = 0.05

a) The null and alternative hypotheses are:

H0 : u = 28.5%

H1 : u < 28.5%

b) Given a 0.05 significance level.

This is a left tailed test.

The critical value =

-Z_0.05 = -1.645

The critical value = -1.645

c) Calculating the test statistic, we have:

Z = \frac{p' - P}{\sqrt{\frac{P(1-P)}{n}}}

Z = \frac{0.2625 - 0.285}{\sqrt{\frac{28.5(1-28.5)}{800}}}

Z = -1.41

d) Decision:

We fail to reject null hypothesis H0, since Z = -1.41 is not in the rejection region, <1.645

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3 years ago
What are the zeros of the polynomial function f(x) = x(x + 5)(x – 8)?
elena-14-01-66 [18.8K]

0,-5,8

To find the zeros, set each equation equal to 0

x=0

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Then solve

x=0

x=-5

x=8

So the zeros are 0,-5, and 8

7 0
3 years ago
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