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elena-s [515]
2 years ago
12

A tin of biscuits contains shortbread and choc-chip biscuits in the ratio 2:3 . The tin contains 80 biscuits. How many short-bre

ad biscuits are there in the tin?
Mathematics
1 answer:
Aleksandr [31]2 years ago
5 0

Answer:

32

Step-by-step explanation:

There are 80 biscuits inside the tin.

Also, they said that those biscuits are in the ratio

Short bread    :      Choc - chip

          2          :        3

Altogether there are 5 shares ( 2 + 3)

And now you can divide 80 by 5 to find how many biscuits contain per a share.

80 ÷ 5 = 16

In the question, they asked us to to find the number of short biscuits inside the tin.

Let us find that.

There are 2 shares for short bread biscuits.

So,

Number of short biscuits ⇒ 2 × 16

                                         ⇒ 32

Hope this helps you :-)

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Graph and label the image of the figure below after a dilation by a factor of 1/2.
neonofarm [45]
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M' (1.5, -1), F' (2, -1), L' (0.5 -2.5), W' (2.5, -2.5)

see graph below

Explanation:

Given:

The image of a quadrilateral on a coordinate plane

To find:

The coordinates of the new image after dilation of 1/2 have been applied to the original image.

Then graph the coordinates

First, we need to state the coordinates of the original image:

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F = (4, -2)

L = (1, -5)

W = (5, -5)

Next, we will apply a scale factor of 1/2:

\begin{gathered} Dilation\text{ rule:} \\ (x,\text{ y\rparen}\rightarrow(kx,\text{ ky\rparen} \\ where\text{ k = scale factor} \\  \\ scale\text{ factor = 1/2} \\ M^{\prime}\text{ = \lparen}\frac{1}{2}(3),\text{ }\frac{1}{2}(-2)) \\ M^{\prime}\text{ = \lparen}\frac{3}{2},\text{ -1\rparen} \\  \\ F\text{ = \lparen}\frac{1}{2}(4),\text{ }\frac{1}{2}(-2)) \\ F^{\prime}\text{ = \lparen2, -1\rparen} \end{gathered}\begin{gathered} L\text{ = \lparen}\frac{1}{2}(1),\text{ }\frac{1}{2}(-5)) \\ L^{\prime}\text{ = \lparen}\frac{1}{2},\text{ }\frac{-5}{2}) \\  \\ W\text{ = \lparen}\frac{1}{2}(5),\text{ }\frac{1}{2}(-5)) \\ W^{\prime}\text{ = \lparen}\frac{5}{2},\text{ }\frac{-5}{2}) \end{gathered}

The new coordinates:

M' (3/2, -1), F' (2, -1), L' (1/2, -5/2), W' (5/2, -5/2)

M' (1.5, -1), F' (2, -1), L' (0.5 -2.5), W' (2.5, -2.5)

Plotting the coordinates:

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