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kondaur [170]
2 years ago
13

A coin is to be tossed as many times as necessary to turn up one head. Thus the elements c of the sample space C are H, TH, TTH,

TTTH, and so forth. Let the probability set function P assign to these elements the respective probabilities 1 2 , 1 4 , 1 8 , 1 16 , and so forth. Show that P(C) = 1. Let C1 = {c : c is H,TH,TTH,TTTH, or TTTTH}. Compute P(C1). Next, suppose that C2 = {c : c is TTTTH or TTTTTH}. Compute P(C2), P(C1 ∩ C2), and P(C1 ∪ C2).
Mathematics
1 answer:
slavikrds [6]2 years ago
5 0

Answer:

Step-by-step explanation:

As stated in the question, the probability to toss a coin and turn up heads in the first try is \frac{1}{2}, in the second is \frac{1}{4}, in the third is \frac{1}{8} and so on. Then, P(C) is given by the next sum:

P(C)=\sum^{\infty}_{n=1}(\frac{1}{2} )^{n}=1

This is a geometric series with factor \frac{1}{2}. Then is convergent to \frac{1}{1-\frac{1}{2}}-1=1.. With this we have proved that P(C)=1.

Now, observe that

P(H)=\frac{1}{2}, P(TH)=\frac{1}{4},P(TTH)=\frac{1}{8},P(TTTH)=\frac{1}{16},P(TTTTH)=\frac{1}{32},P(TTTTTH)=\frac{1}{64}.

Then

P(C1)=P(H)+P(TH)+P(TTH)+P(TTTH)+P(TTTTH)=\frac{1}{2} +\frac{1}{4} +\frac{1}{8} +\frac{1}{16} +\frac{1}{32} =\frac{31}{32}

P(C2)=P(TTTTH)+P(TTTTTH)=\frac{1}{32}+\frac{1}{64} =\frac{3}{64}

P(C1\cap C2)=P(TTTTH)=\frac{1}{32}

and

P(C1\cup C2)=P(H)+P(TH)+P(TTH)+P(TTTH)+P(TTTTH)+P(TTTTTH)=\frac{1}{2} +\frac{1}{4} +\frac{1}{8} +\frac{1}{16} +\frac{1}{32} +\frac{1}{64}=\frac{63}{64}

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Answer:

5\frac{22}{25}\ hours

Step-by-step explanation:

we know that

4\frac{1}{5}\ hours=\frac{4*5+1}{5}=\frac{21}{5}\ hours

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Let

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x=\frac{140}{100} (\frac{21}{5})=\frac{2,940}{500}\ hours

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\frac{2,940}{500}=\frac{2,500}{500}+\frac{440}{500}=5\frac{22}{25}\ hours

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Michael invested 5,000 in an account that has a 5.5% annual interest rate. What equation best describes investment after T years
ivolga24 [154]

Answer:

V = 5000 +  275*T   for simple annual interest

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Step-by-step explanation:

I assume this is a simple interest rate.  If not I will give the one for compound interest.

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2 years ago
Which equation correctly shows the multiplication of the means and extremes in the proportion 7.2∕9.6 = 21.6∕28.8?
vampirchik [111]

Which equation correctly shows the multiplication of the means and extremes in the proportion 7.2 ∕ 9.6 = 21.6 ∕ 28.8?

a. 7.2 ⋅ 9.6 = 21.6 ⋅ 28.8

b. 9.6 ⋅ 21.6 = 28.8 ⋅ 7.2

c. 7.2 ⋅ 21.6 = 28.8 ⋅ 9.6

d. 7.2 ⋅ 28.8 = 21.6 ⋅ 28.8

Answer:

b. 9.6 ⋅ 21.6 = 28.8 ⋅ 7.2

Step-by-step explanation:

When a proportion say a/b = c/d is given, the outer terms are called the extremes while the inner/middle terms are called the means.

In the case of a / b = c / d,

the outer terms are a and d

the inner terms are b and c

Often times, we find the cross products of the proportion to test whether the two ratios in the proportion are equal. To do that, we find the product of the extremes and equate it to the product of the means.

In the case of a / b = c / d,

the cross products are a x d and b x c

So if a x d = b x c, then a/b = c/d is a true proportion.

Now to the question;

Given proportion: 7.2 / 9.6 = 21.6 / 28.8

Extremes = 7.2 and 28.8

Means = 9.6 and 21.6

The correct multiplication of the means and extremes is therefore

9.6 x 21.6 = 7.2 x 28.8

or

9.6 · 21.6 = 7.2 · 28.8

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