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irina1246 [14]
3 years ago
6

create two scenarios of your own that involve relations in real life. Describe the scenarios in detail, including a description

of the two variables involved and data for each of the variables. Then create either a table, a mapping diagram, or a graph to represent the data in each scenario. Include at least three data points in your representation. Use a different way to represent the relation for each of your scenarios.
Mathematics
1 answer:
Lorico [155]3 years ago
7 0
Here's one example.

1) Catering Costs

"celebrations" offers catering services. They charge 30 dollars initially, and 1.5 dollars per person.

a) C representing cost and P representing people. The equation of this relation is C = 1.5p + 30

b)  C   P
    32   1
  33.5  2
    35   3
  36.5  4

(The table can be used to make points)
(p,C)

c) You can rewrite this in standard form.
  
   C = 1.5t + 30
   0 = 1.5t - C + 30
-30 = 1.5t - C
 30 = -1.5t + C

Another example:

2) Transportation.

A car is driving from City A to City B at a constant speed of 80km/h The distance away from both cities is 240km.

a) In which D represents distance in km and T represents time in hours, an equation that can represent the distance away from City B is D = -80t + 240

b) D   t
  160  1
   80   2
    0    3
  
(These can be used to make points)

c) You can rewrite in standard form.

D = -80t + 240
0 = -80t - D + 240
-240 = -80t - D
240 = 80t + D

brainliest?

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Tcecarenko [31]
660 divided by 2 and it gives you your answer of 13.2
So therefore the answer is 13.2 per hour
8 0
3 years ago
The Wall Street Journal Corporate Perceptions Study 2011 surveyed readers and asked how each rated the Quality of Management and
kykrilka [37]

Answer:

The calculated χ² =  <u>17.0281</u>    falls in the critical region χ² ≥  9.49  so we reject the null hypothesis that  the quality of management and the reputation of the company are independent and conclude quality of management and the reputation of the company are dependent

The p-value is 0 .001909. The result is significant at p < 0.05

Part b:

40 > 8.5

35> 7.5

25> 4

Step-by-step explanation:

1) Let the null and alternative hypothesis as

H0: the quality of management and the reputation of the company are independent

against the claim

Ha: the quality of management and the reputation of the company are dependent

2) The significance level alpha is set at 0.05

3) The test statistic under H0 is

χ²= ∑ (o - e)²/ e where O is the observed and e is the expected frequency

which has an approximate chi square distribution with ( 3-1) (3-1)=  4 d.f

4) Computations:

Under H0 ,

Observed       Expected E              χ²= ∑(O-e)²/e

40                      35.00                          0.71

25                      24.50                         0.01

5                         10.50                         2.88  

35                      40.00                         0.62

35                      28.0                          1.75

10                       12.00                           0.33  

25                      25.00                             0.00

10                        17.50                              3.21

<u>15                       7.50                                 7.50  </u>

<u>∑                                                               17.0281</u>

     

     

Column Totals 100 70 30   200  (Grand Total)

5) The critical region is χ² ≥ χ² (0.05)2 = 9.49

6) Conclusion:

The calculated χ² =  <u>17.0281</u>    falls in the critical region χ² ≥  9.49  so we reject the null hypothesis that  the quality of management and the reputation of the company are independent and conclude quality of management and the reputation of the company are dependent.

7) The p-value is 0 .001909. The result is significant at p < 0.05

The p- values tells that the variables are dependent.

Part b:

If we take the excellent row total = 70 and compare it with the excellent column total= 100

If we take the good row total = 70 and compare it with the good column total= 80

If we take the fair row total = 50 and compare it with the fair column total= 30

The two attributes are said to be associated if

Thus we see that ( where (A)(B) are row and columns totals and AB are the cell contents)

AB> (A)(B)/N  

40 > 1700/200

40 > 8.5

35> 1500/200

35> 7.5

25> 800/200

25> 4

and so on.

Hence they are positively associated

8 0
3 years ago
What's the correlation coefficient of this date . 10,11,16,9,7,15,16,10,96,51,62,58,89,81,46,51
dem82 [27]
Assuming the question is in the wrong format and"date" is data.
I chose X= 10,11,16,9,7,15,16,10 and Y= <span>96,51,62,58,89,81,46,51
the correlation cooefficent is -0.3351

</span>

8 0
3 years ago
Please help me! I will mark brainliest!
Elenna [48]

Answer:

Your picture didn't load?

Step-by-step explanation:

3 0
3 years ago
Why is the rise the value for the numerator and the run the value for the denominator?
julsineya [31]
Because change in y for the rise is if it goes up or down and change in x for the run to see if it goes left or right
3 0
3 years ago
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