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2 years ago

Question: Replace the question mark in the above problem with the appropriate number.

Mathematics

2 answers:

11Alexandr11 [23.1K]2 years ago

7 0

Answer: its 6.

Have a great day/night!

Westkost [7]2 years ago

6 0

its 6

Step-by-step explanation:

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The dot plot represents the prices of different brands of chocolate bars.

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The answer is simply C.$2.50

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3 years ago

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What is the beat values of averages, such as mean, median, and mode, are known as

IrinaVladis [17]

A) Standard deviation

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3 years ago

Sum of two numbers is 42 and their difference is 8 . Find the numbers ?

worty [1.4K]

Answer:

25 and 17

Step-by-step explanation:

25+17=42

25-17=8

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2 years ago

three and four angles below form a triangle which of the angles to do not belong 35 degrees 115 degrees 50 degrees 30 degrees

aleksandrvk [35]

50 degrees doesn’t belong because

35 + 115 + 30 = 180 degrees

Hope this helped :)

7 0

3 years ago

An apartment complex rents an average of 2.3 new units per week. If the number of apartment rented each week Poisson distributed

masya89 [10]

Answer:

$P(X\leq 1) = 0.331$

Step-by-step explanation:

Given

Poisson Distribution;

Average rent in a week = 2.3

Required

Determine the probability of renting no more than 1 apartment

A Poisson distribution is given as;

$P(X = x) = \frac{y^xe^{-y}}{x!}$

Where y represents λ (average)

y = 2.3

Probability of renting no more than 1 apartment = Probability of renting no apartment + Probability of renting 1 apartment

Using probability notations;

$P(X\leq 1) = P(X=0) + P(X =1)$

Solving for P(X = 0) [substitute 0 for x and 2.3 for y]

$P(X = 0) = \frac{2.3^0 * e^{-2.3}}{0!}$

$P(X = 0) = \frac{1 * e^{-2.3}}{1}$

$P(X = 0) = e^{-2.3}$

$P(X = 0) = 0.10025884372$

Solving for P(X = 1) [substitute 1 for x and 2.3 for y]

$P(X = 1) = \frac{2.3^1 * e^{-2.3}}{1!}$

$P(X = 1) = \frac{2.3 * e^{-2.3}}{1}$

$P(X = 1) =2.3 * e^{-2.3}$

$P(X = 1) = 2.3 * 0.10025884372$

$P(X = 1) = 0.23059534055$

$P(X\leq 1) = P(X=0) + P(X =1)$

$P(X\leq 1) = 0.10025884372 + 0.23059534055$

$P(X\leq 1) = 0.33085418427$

$P(X\leq 1) = 0.331$

Hence, the required probability is 0.331

6 0

2 years ago