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3 years ago

Please help me please

Mathematics

2 answers:

Olegator [25]3 years ago

6 0

$\huge \green{Answer}$

$\: \tt → 94cm {}^{2}$

$\bf \: Given : \\ \tt Length(l) = 5cm \\ \tt \: breadth(b) = 4cm \\ \tt \: height(h) = 3cm \\ \\ \bf \: Apply \: formula : \\ \bf \tt \: Surface \: \: area \: \: of \: \: a \: \: cuboid \: \\ \tt \: = >2(lb + bh + hl) \\ \\ \tt = > 2(5 \times 4 + 4 \times 3 + 3 \times 5) \\ \tt \: = > 2(47)cm \\ \\ \tt = > {94cm}^{2}$

Ksenya-84 [330]3 years ago

5 0

Answer: 94cm squared

Step-by-step explanation:

Surface area is the sum of the areas of all faces (or surfaces) on a 3D shape. A cuboid has 6 rectangular faces. To find the surface area of a cuboid, add the areas of all 6 faces. We can also label the length (l), width (w), and height (h) of the prism and use the formula, SA=2lw+2lh+2hw, to find the surface area.

2(12) + 2(15) + 2(20)=

24 + 30 + 40 =

54 + 40=

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3 years ago

Write the equation in standard form of a circle with center (-7,2), tangent to the y-axis.

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Answer:

$(x+7)^2+(y-2)^2=7^2$

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Tangent to y-axis means that the side of the circle TOUCHES the y axis.

Since the center is at (-7,2) and it touches the y axis, we can figure out the radius. It goes from (-7,2) to y-axis. Horizontally, the center is 7 units left of y-axis, so that is the radius ----- 7 units

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$(x-h)^2+(y-k)^2=r^2$

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Putting the information into the form, we have:

$(x-h)^2+(y-k)^2=r^2\\(x-(-7))^2+(y-(2))^2=7^2\\(x+7)^2+(y-2)^2=7^2$

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3 years ago

How do u solve 2/3times 5/6times 14

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3 years ago

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Find the value of tan F rounded to the nearest hundredth , if necessary

spin [16.1K]

Using it's formula, it is found that the tangent of F is given by:

$\tan{F} = \frac{6\sqrt{85}}{85}$

<h3>How to find the tangent of an angle?</h3>

In a right triangle, the tangent of an angle is given by the length of the opposite leg divided by the length of the adjacent leg.

Researching the problem in the internet, it is found that for the <em>right triangle</em> in this problem:

The length of the opposite leg to angle F is of 6.

The length of the adjacent leg to angle F is of x.

The length of the hypotenuse is of 11.

Applying the Pythagorean Theorem, we have that:

$6^2 + x^2 = 11^2$

$36 + x^2 = 121$

$x^2 = 85$

$x = \sqrt{85}$

Considering that the tangent is the length of the opposite leg divided by the length of the adjacent leg, we have that:

$\tan{F} = \frac{6}{\sqrt{85}} \times \frac{\sqrt{85}}{\sqrt{85}} = \frac{6\sqrt{85}}{85}$

To learn more about tangent, you can take a look at brainly.com/question/24680641

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3 years ago

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ikadub [295]

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4 years ago

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Please help me please​

Please help me please