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True [87]
3 years ago
5

Question 6

Mathematics
1 answer:
vaieri [72.5K]3 years ago
7 0

Answer:

65.7 mg/l.

Step-by-step explanation:

Answer:

A. 65.7 mg/l.

B. iv. No. The average chlorine compound concentration (mg/l) is too high.

Step-by-step explanation:

Given:

Outflow = 36%

= 36 l in 100 l of wetland

Seepage = 47%

= 47 l in 100 l of wetland

Evaporates = 8%

= 8 l in 100 l of wetland

Water volume = 9%

= 36 l in 100 l of wetland

Outflow = 53.6 mg/l

Seepage = 73.9mg/l

Remaining due to evaporation = 57.0mg/l

Water volume = 74.0 mg/l

Concentration of Chlorine compounds:

Outflow = 36/100 * 53.6

= 19.3 mg/l of outflow chlorine in the wetlands.

Seepage = 47/100 * 73.9

= 34.73 mg/l of seepage chlorine in the wetlands.

Evaporates = 8/100 * 57

= 4.56 mg/l of evaporates chlorine in the wetlands.

Water volume = 9/100 * 74

= 6.66 mg/l of outflow chlorine in the wetlands.

Weighted average concentration of chlorine compounds in 100 l of wetland = total(X*W)/totalW

Where,

Total w = 0.36 + 0.47 + 0.08 + 0.09

= 1

Total X*W = 19.3 + 34.73 + 4.56 + 6.66

= 65.65/1

= 65.7 mg/l.

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