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alexdok [17]
3 years ago
6

Help, giving 40 points and brainly 6^2 x 7 gvbkjw4goeqvl

Mathematics
2 answers:
Sever21 [200]3 years ago
7 0

Answer: 252 i think

Step-by-step explanation:

Masteriza [31]3 years ago
3 0

Answer:

252

Step-by-step explanation:

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-2y + 6 = -12 lol how do i solve that again??
vagabundo [1.1K]

Answer:

y=9

Step-by-step explanation:

-2y + 6 = -12

-2y - 6 = -6

-2y = -18

-2/y= -18/-2

y= 9

5 0
4 years ago
Read 2 more answers
The equation a=1/2(b^1+b^2)h can be determined the area, a, of a trapezoid with height, h, and base lengths, b^1 and b^2 Which a
Evgesh-ka [11]

The complete question is as follows.

The equation a = \frac{1}{2}(b_1 + b_2 )h can be used to determine the area , <em>a</em>, of a trapezoid with height , h, and base lengths, b_1 and b_2. Which are equivalent equations?

(a) \frac{2a}{h} - b_2 = b_1

(b) \frac{a}{2h} - b_2 = b_1

(c) \frac{2a - b_2}{h} = b_1

(d) \frac{2a}{b_1 + b_2} = h

(e) \frac{a}{2(b_1 + b_2)} = h

Answer: (a) \frac{2a}{h} - b_2 = b_1; (d) \frac{2a}{b_1 + b_2} = h;

Step-by-step explanation: To determine b_1:

a = \frac{1}{2}(b_1 + b_2 )h

2a = (b_1 + b_2)h

\frac{2a}{h} = b_1 + b_2

\frac{2a}{h} - b_2 = b_1

To determine h:

a = \frac{1}{2}(b_1 + b_2 )h

2a = (b_1 + b_2)h

\frac{2a}{(b_1 + b_2)} = h

To determine b_2

a = \frac{1}{2}(b_1 + b_2 )h

2a = (b_1 + b_2)h

\frac{2a}{h} = (b_1 + b_2)

\frac{2a}{h} - b_1 = b_2

Checking the alternatives, you have that \frac{2a}{h} - b_2 = b_1 and \frac{2a}{(b_1 + b_2)} = h, so alternatives <u>A</u> and <u>D</u> are correct.

4 0
4 years ago
For what values of n is the sum (−27.1+3n)+(7.1+5n) negative?
astraxan [27]

Answer: n = 0 to 2

n = - infinity to -1

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
I need some help solving two equations on my Algebra 1 homework
EleoNora [17]
1. y < -x - 5......(-3,-4)
2. 5x - 3y < = 15.....all of ur answers satisfy this inequality
5 0
3 years ago
1. Given: AB = 64; M lies on the line AB
Gnom [1K]

Answer:

Step-by-step explanation:

Given the following lengths AB = 64, AM = 4x + 4 and BM= 6x-10, If M lies on the line AB  then AM+MB = AB (addition property)

Substituting the given parameters into the addition property above;

AM+MB = AB

4x + 4 + 6x - 10 = 64

combine like terms

4x+6x = 64+10-4

10x = 74-4

10x = 70

Divide both sides by 10

x = 70/10

x = 7

Note that for M to be the midpoint of AB then AM must be equal to BM i.e AM = BM

To get AM ;

Since AM = 4x+4

substitute x = 7 into the function

AM = 4(7)+4

AM = 28+4

AM = 32

Similarly, BM = 6x-10

BM = 6(7)-10

BM = 42-10

BM = 32

<em></em>

<em>Since AM = BM = 32,. then M is the midpoint of AB</em>

6 0
4 years ago
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