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Iteru [2.4K]
3 years ago
7

What is the length of the radius, r? 6 cm 18 cm 36 cm 72 cm.

Mathematics
1 answer:
Rus_ich [418]3 years ago
7 0

The length of the radius of circle o is 18 cm.

<h2></h2><h2>Given that</h2>

Circle o has a circumference of 36π cm.

<h3>We have to determine</h3>

What is the length of the radius, r?

<h3>According to the question</h3>

Circle o has a circumference of 36π cm.

The length of the radius of the circle is determined by the following formula;

\rm Circumference = 2\pi r

Substitute all the values in the formula;

\rm Circumference = 2\pi r\\&#10;\\&#10;36\pi =2\pi r\\&#10;\\&#10;r = \dfrac{36\pi }{2\pi }\\&#10;\\&#10;r = 18 \ cm

Hence, the length of the radius of circle o is 18 cm.

To know more about Circumference click the link given below.

brainly.com/question/4268218

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Each tie costs $25.50, and each hat costs $6.00.

Because 51.00 divided by 2 equals 25.5 (which is the cost for a tie), and 25.5 times 3 equals 76.5. Then 88.50- 76.50 = 12, and 12/2 equals 6 which is the cost for each hat.
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Mariah spent $9.50 on 9 pounds of limes and pears. Limes cost $0.50 per pound and pears cost $1.50 per pound. Let l be the numbe
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Katie is comparing the prices of packages of paper cups. One brand costs c dollars and contains 80 cups per package. Another bra
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A pharmacy claims that the average medication costs $32 but it could differ as much as $8. Write and solve an absolute value ine
Vinil7 [7]

Answer:

Therefore, Option C is correct that is |x-32|\leq8|{\text{the medication costs range from $24to $40}.

Step-by-step explanation:

We have given medication cost $32

Since, we have given as much as 8 so the inequality will maximum goes upto 8.

|x-32|\leq8

Now, we will solve the inequality for x we will get

We will first open the modulus function by its definition we will get

which is |x| is +x  and -x

(x-32)\leq8

x=32+8=40

x=40

And -(x-32)\leq8

-x+32=8

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Therefore, Option C is correct

8 0
3 years ago
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Construct a​ 95% confidence interval for the population standard deviation sigma of a random sample of 15 crates which have a me
Ad libitum [116K]

Answer:

There is a 95% confidence that the sample has a mean between 158.92 pounds and 171.48 pounds

Step-by-step explanation:

Given that mean (μ) = 165.2 pounds, standard deviation (σ) = 12.4 pounds, sample size (n) = 15 crates. Confidence (C) = 95% = 0.95

α = 1 - C = 1 - 0.95 = 0.05

α/2 = 0.05/2 = 0.025

The z score of α/2 corresponds to the z score of 0.475 (0.5 - 0.025) which is 1.96. z_{\frac{\alpha}{2} }=1.96

The margin of error (E) is given by:

E=z_{\frac{\alpha}{2} }\frac{\sigma}{\sqrt{n} } =1.96*\frac{12.4}{\sqrt{15} }= 6.28

The confidence interval = μ ± E = 165.2 ± 6.28 = (158.92, 171.48)

The confidence interval is between 158.92 pounds and 171.48 pounds. There is a 95% confidence that the sample has a mean between 158.92 pounds and 171.48 pounds

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