Question

9. Find the area of the figure to the right. area 14 in

Answer 1

Answer:

1. 200 in.^2

2.

Step-by-step explanation:

1. Area of a trapezium=1/2(a+b)height

a=14 in.

b=20 in.+6 in. = 26 in.

height= ?

height can be gotten by using

formula : Soh Cah Toa

Toa is tangent∆= opposite/ adjacent

∆ = 60°

opp=? adj=6 in.

Tan 60° =opp/6 in.

Tan 60° = 1.732

1.732= opp/ 6 in.

opp=1.732*6 in.

opp = 10.392 approximately= 10 in.

Area of trapezium= 1/2*(14+26)*10(in.^2)

Area of trapezium= 1/2*40*10

= 1/2*400

= 200 in.^2 .

2. Area of triangle= 1/2* base* height

for first triangle =

base=4m

height =15m

Area: 1/2*4*15 ,1/2*60= 30m^2

second triangle =

base:?

height: 15m

using Pythagorean theorem;

hyp^2 = opposite ^2 + adjacent ^2

17^2 = 15^2 + adj^2

289= 225 + adj^2

adj^2 = 289-225= 64

square root

adj = 8m

area of second triangle : 1/2*8*15

: 1/2*120 :60m^2

total area: 30 m^2 +60m^2

==90 m^2