<span>83 as a sum of 8 tens and 3 ones
.....................................</span>
Answer:
h=22.5167 x 10^0
Step-by-step explanation:
Answer:
around 51.78
Step-by-step explanation:
do 246÷4.75 which is around 51.78
The least common multiple of each pair of the polynomial (5y² - 80) and
(y + 4) is equal to 5(y-4)(y+4).
As given in the question,
Given pair of the polynomial is (5y² - 80) and (y + 4)
Simplify the given polynomial using (a² -b²) = (a-b)(a +b)
(5y² - 80) = 5(y² -16)
⇒(5y² - 80) = 5(y² - 4²)
⇒(5y² - 80) = 5(y -4)(y + 4)
And (y + 4) = (1) (y+4)
Least common multiple = 5(y-4)(y+ 4)
Therefore, the least common multiple of the given pair of the polynomial is 5(y -4)(y+ 4).
Learn more about least common multiple here
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Answer: f(-2) = -6
Step-by-step explanation: f(-2) = -2 -4
f(-2) = -6
