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sergij07 [2.7K]
3 years ago
5

Which atom has the largest atomic radius? * 1.Cl 2.F 3.I

Chemistry
1 answer:
puteri [66]3 years ago
6 0

Answer: 2

Explanation:I think

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The number of molecules in 1.00 liter of O2 gas at 56◦C and 821 torr is
enot [183]

Answer:

2. 2.41 x 10^22 molec

Explanation:

3 0
3 years ago
In the background information, it was stated that CaF2 has solubility, at room temperature, of 0.00160 g per 100 g of water. How
____ [38]

Answer:

2.05*10⁻⁵ moles of CF₂ can dissolve in 100 g of water.

12.82 moles of CaF₂ will dissolve in exactly 1.00 L of solution

Explanation:

First, by definition of solubility, in 100 g of water there are 0.0016 g of CaF₂. So, to know how many moles are 0.0016 g, you must know the molar mass of the compound. For that you know:

  • Ca: 40 g/mole
  • F: 19 g/mole

So the molar mass of CaF₂ is:

CaF₂= 40 g/mole + 2*19 g/mole= 78 g/mole

Now you can apply the following rule of three: if there are 78 grams of CaF₂ in 1 mole, in 0.0016 grams of the compound how many moles are there?

moles=\frac{0.0016 grams*1 mole}{78 grams}

moles=2.05*10⁻⁵

<u><em>2.05*10⁻⁵ moles of CF₂ can dissolve in 100 g of water.</em></u>

Now, to answer the following question, you can apply the following rule of three: if by definition of density in 1 mL there is 1 g of CaF₂, in 1000 mL (where 1L = 1000mL) how much mass of the compound is there?

mass of CaF_{2}=\frac{1000 mL*1g}{1mL}

mass of CaF₂= 1000 g

Now you can apply the following rule of three: if there are 78 grams of CaF₂ in 1 mole, in 1000 grams of the compound how many moles are there?

moles=\frac{1000 grams*1 mole}{78 grams}

moles=12.82

<u><em>12.82 moles of CaF₂ will dissolve in exactly 1.00 L of solution</em></u>

5 0
3 years ago
What is it’s molecular formula for C5H4 if it’s molar mass is 128.17g/mol
Anna [14]
<h2>Answer :</h2><h3><u>QUESTION ①)</u></h3>

✔ C5H4 has a molecular molar mass of :

<em>M(C5H4) = 5 x M(C) + 4 x M(H) </em>

  • M(C5H4) = 5 x 12 + 4 x 1
  • M(C5H4) = 60 + 4
  • M(C5H4) = 64 g/mol

✔ The molecular mass of C5H4 is therefore 64 g/mol.

  • But, 128/64 = 2
<h3>This is double the molar mass of C5H4, this molecule has the formula 2C5H4.</h3>
7 0
3 years ago
Hemos preparado la siguiente disolución 40 g de sal en 250 g de agua. Escribe:
Anestetic [448]
Calcula el Tanta por ciento en peso de soluto
5 0
4 years ago
How many molecules are in 5.75 mol HBr
DerKrebs [107]

Answer:

3.46 x 10²⁴ molecules.

Explanation:

  • <em>Knowing that every one mole of a substance contains Avogadro's no. of molecules (NA = 6.022 x 10²³).</em>

<em><u>Using cross multiplication:</u></em>

1.0 mole of HBr → 6.022 x 10²³ molecules.

5.75 mole of HBr → ??? molecules.

∴ The no. of molecules of HBr are in 5.75 mol = (6.022 x 10²³ molecules) ( 5.75 mole) / (1.0 mol) = 3.46 x 10²⁴ molecules.

7 0
3 years ago
Read 2 more answers
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