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larisa86 [58]
3 years ago
9

Whats the answer for 3(h-5g) while using distributive property

Mathematics
1 answer:
Schach [20]3 years ago
3 0

Answer:

3h - 15g

Step-by-step explanation:

All you have to do is multiply 3 by h, and 3 by 5g, but you have to keep the subtraction, so it would be 3h - 15g

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4 0
3 years ago
The rain barrel shown is a right circular cylinder. If 1ft^3=7.5 gallons, how many gallons of rainwater can the barrel hold if t
valentina_108 [34]

this can be solved using the fomula of the volume of a right circular cylinder

V = pi*r^2*h

Where pi = 3.1416

R is the radius

H is the height

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V = 44.3342 ft^3 (7.5 gallon / 1 ft^3)

<span>V = 332.5062 gallons</span>

6 0
3 years ago
The selling price of a skateboard is $147. The store has a 75% markup policy. What is the cost of the skateboard to the store?
Maru [420]
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5 0
3 years ago
Read 2 more answers
Extra points and top BRAINIEST!!!Westin is comparing the triangles below.
UkoKoshka [18]

∠H = ∠J = 27°


∠G = ∠L = 117°


∠F = 180 - (∠H + ∠G) = 180 - (27+117) = 36°


∠K = 180 - (∠J + ∠L ) = 180 - (27+117) = 36°


∴∠F = ∠K = 36°


∴ ΔHGF is similar to ΔJLK


So, the correct statement ⇒ HG and LJ are proportional.


======================================



5 0
4 years ago
Statistics professors believe the average number of headaches per semester for all students is more than 18. From a random sampl
kompoz [17]

Complete Question

Statistics professors believe the average number of headaches per semester for all students is more than 18. From a random sample of 15 students, the professors find the mean number of headaches is 19 and the standard deviation is 1.7. Assume the population distribution of number of headaches is normal.the correct conclusion at \alpha =0.001 is?

Answer:

There is no sufficient evidence to support the professor believe

Step-by-step explanation:

From the question we are told that

     The population mean is  \mu =  18

     The sample size is  n  =  15

      The sample mean is  \=  x  =  19

      The standard deviation is  \sigma =  1.7

      The level of significance is  \alpha  =  0.001

The null hypothesis is  H_o:  \mu = 18

The  alternative hypothesis is  H_a :  \mu > 18

 The critical value of the level of significance from the normal distribution table is    

         Z_{\alpha } =  3.290527

The test hypothesis is mathematically represented as

           t =  \frac{\= x  -  \mu }{ \frac{\sigma}{ \sqrt{n} } }

substituting values  

         t =  \frac{ 19  - 18}{ \frac{1.7}{ \sqrt{15} } }

         t =  2.28

Looking at the value of  t and  Z_{\alpha } we can see that t <  Z_{\alpha } so we fail to reject the null hypothesis.

This mean that there is no sufficient evidence to support the professor believe

     

       

3 0
4 years ago
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