3 years ago

3.4.4 Journal: Exponential vs. Quadratic

Mathematics

1 answer:

zysi [14]3 years ago

5 0

Answer:

what's the question your asking for?

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Step-by-step explanation:

Let

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P(Y) - Probability that he had ate dinner,

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P( $Y^{C}$ | X ) = $\frac{P( X | Y^{C} ). P(Y^{C} ) }{P( X | Y^{C} ). P(Y^{C} ) + P( X | Y ) . P (Y) }$

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P(Y | $X^{C}$ ) = $\frac{(1 - P(X | Y ) ) . P(Y)}{P( X^{C} ) } = \frac{(1 - P(X | Y ) ) . P(Y)}{ 1 - P( X ) }$

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