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JulsSmile [24]
2 years ago
12

Let the function f be defined by f (x) = 5x - 2a,

Mathematics
1 answer:
seraphim [82]2 years ago
6 0

Answer: 5

Step-by-step explanation:

f(10)=50-2a\\\\f(5)=25-2a\\ \\ f(10)+f(5)=75-4a=55 \implies a=5

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ladessa [460]

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3 0
2 years ago
Read 2 more answers
Chris buys 8 more Ninja Turtles than Star Wars action figures. The Ninja Turtles cost $7 each and the Star Wars cost $9 each. Wr
Natalka [10]

Answer:

Total Cost, C=$(16S +56)

Step-by-step explanation:

Chris buys 8 more Ninja Turtles than Star Wars action figures.

Cost of each Ninja Turtle = $7

Cost of each Star Wars  = $9

Let number of Star Wars bought = S

As per question statement, number of Ninja Turtles bought = S+8

Cost of 'S' number of Star Wars = Number of Star Wars bought \times cost of each Star Wars

Total cost of Star Wars bought = S \times 9 or $9S

Similarly, Cost of 'S+8' number of Ninja Turtles = Number of Ninja Turtles bought \times cost of each Ninja Turtles

Total cost of Ninja Turtles bought = (S+8) \times 7 or $(7S +56)

Total Cost of the purchase = Total cost of Star Wars Bought + Total cost of Ninja Turtles bought

Total Cost of the purchase, C = 9S + (7S +56)

\Rightarrow C=\$(16S +56)

4 0
3 years ago
How do I evaluate the expression? What steps do I take?
Bingel [31]

Answer:

\frac{4+8-2}{6-4}*3-1=\frac{12-2}{2}*3-1\\\\=\frac{10}{2}*3-1=5*3-1=15-1=14

Step-by-step explanation:

8 0
3 years ago
What is The value of X?
Vladimir79 [104]

Answer:

Step-by-step explanation:

a) x=24

b) x=20

5 0
4 years ago
Randall wants to mix 50 lb of nuts worth $2 per lb with some nuts worth $7 per lb to make a mixture worth $6 per lb. How many po
defon

A = nuts of $2/lb

B = nuts of $7/lb


let's say we'll mix "x" lbs of B to get a mixture with A of "y" lbs, therefore


\bf \begin{array}{lcccl} &\stackrel{lbs}{quantity}&\stackrel{\textit{cost}}{per~lb}&\stackrel{\textit{cost}}{total}\\ \cline{2-4}&\\ A~ nuts&50&2&100\\ B~nuts&x&7&7x\\ \cline{2-4}&\\ mixture&y&6&6y \end{array} \\\\\\ \begin{cases} 50+x=\boxed{y}\\ 100+7x=6y \end{cases}\qquad \qquad \implies 100+7x=6\left( \boxed{50+x} \right) \\\\\\ 100+7x=300+6x\implies \blacktriangleright x=200 \blacktriangleleft

3 0
3 years ago
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