2 years ago

Let the function f be defined by f (x) = 5x - 2a,

Mathematics

1 answer:

seraphim [82]2 years ago

6 0

Answer: 5

Step-by-step explanation:

$f(10)=50-2a\\\\f(5)=25-2a\\ \\ f(10)+f(5)=75-4a=55 \implies a=5$

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Find an equation for the line with the given properties. Perpendicular to the line 7x - 3y = 68; containing the point (8, -8)

Sever21 [200]

Answer:

$y=\dfrac{-3}{7}x-\dfrac{32}{7}$

Step-by-step explanation:

Given that,

A line 7x - 3y = 68 and containing the point (8, -8).

The equation can be written as :

$-3y=68-7x\\\\y=\dfrac{68}{-3}+\dfrac{7x}{3}\\\\y=\dfrac{7x}{3}+(\dfrac{-68}{3})$

The slope is :7/3

Line is perpendicular so use m = –3/7

$-8=(-\dfrac{3}{7})\times 8+b\\\\-8+\dfrac{3}{7}\times 8=b\\\\b=\dfrac{-32}{7}$

So, required equation is :

$y=\dfrac{-3}{7}x-\dfrac{32}{7}$

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HELP!

Ber [7]

A)
8^2+9^2=c^264+81=c^2
c^2=145c=sqrt 145c=12.04
B)
Pythagerean Theorum:
A^2+B^2=C^2, where C is the hypotenuse and A and B are the other legs
15^2=9^2+B^2
225=81+B^2
225-81=B^2
144=B^2 (square root both sides)
12=B

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