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kotegsom [21]
3 years ago
6

Melissa wants to buy a $25 hat.

Mathematics
1 answer:
slega [8]3 years ago
5 0
Just know that you are smart and that you can do this
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2/3 5/7 16/21 smalledr to biggedt
saul85 [17]

Answer:

Step-by-step explanation:

Yes

7 0
3 years ago
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The product of the roots of 5 - 2m - 3m^2 = 0 is:<br> A. -5/3<br> B. -3/5<br> C. 5/3
dimaraw [331]
<span>m= <span><span><span><span>−5/</span>3 </span></span></span></span><span>   ,swnkadkjkkjmd,m,mdas</span>
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Solve the initial value problem y'=2 cos 2x/(3+2y),y(0)=−1 and determine where the solution attains its maximum value.
zloy xaker [14]

Answer:

y=\frac{-3\pm\sqrt{4sin2x+1}}{2}

x={\pi}{4}

Step-by-step explanation:

We are given that

y'=\frac{2cos2x}{3+2y}

y(0)=-1

\frac{dy}{dx}=\frac{2cos2x}{3+2y}

(3+2y)dy=2cos2x dx

Taking integration on both sides then we get

\int (3+2y)dy=2\int cos 2xdx

3y+y^2=sin2x+C

Using formula

\int x^n=\frac{x^{n+1}}{n+1}+C

\int cosx dx=sinx

Substitute x=0 and y=-1

-3+1=sin0+C

-2=C

sin0=0

Substitute the value of C

y^2+3y=sin2x-2

y^2+3y-sin 2x+2=0

y=\frac{-3\pm\sqrt{(3)^2-4(1)(-sin2x+2)}}{2}

By using quadratic formula

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

y=\frac{-3\pm\sqrt{9+4sin2x-8}}{2}=\frac{-3\pm\sqrt{4sin2x+1}}{2}

Hence, the solution y=\frac{-3\pm\sqrt{4sin2x+1}}{2}

When the solution is maximum then y'=0

\frac{2cos2x}{3+2y}=0

2cos2x=0

cos2x=0

cos2x=cos\frac{\pi}{2}

cos\frac{\pi}{2}=0

2x=\frac{\pi}{2}

x=\frac{\pi}{4}

3 0
3 years ago
Find the sum of 12/13 +(-1/3)
Arlecino [84]

Answer:

23/39

Step-by-step explanation:

Step 1:

12/13 + ( - 1/3 )

Step 2:

36/39 - 13/39

Answer:

23/39

Hope This Helps :)

5 0
3 years ago
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