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adoni [48]
2 years ago
14

Francis is at the state fair. A fair concession stand is selling funnel cakes for $3.50 and deep-fried Oreos for $2.00. Write an

equation in standard form that models the number of funnel cakes x and the number of deep fried oreos y Francis can buy if he spends $42.00.
Mathematics
1 answer:
VladimirAG [237]2 years ago
3 0

The equation that models the number of funnel cakes and Oreos he can buy is 3.50x + 2.0y = 42

Data given;

  • Cost of cakes = $3.50
  • Cost of Oreos = $2.00
  • The total amount spent = $42.00
<h3>What is the Equation</h3>

To solve this problem, we just need to write out an equation to show how he can spend $42.00 in the fair on Oreos and Cakes.

Let x represent the cakes

Let y represent the Oreos

The equation is thus;

3.50x + 2.0y = 42.00

The equation that shows the number of Cakes and Oreos can by is

3.50x + 2.0y = 42

Learn more about equation here;

brainly.com/question/13729904

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Erica is a sheep farmer. She is having a problem with wolves attacking the flock. She starts with an initial 200 sheep and notic
Free_Kalibri [48]

The equation for the situation is y=200(\frac{2}{3})^{x}

It will take around 9 years for her to have around 5 sheep

Step-by-step explanation:

The exponential decay growth/decay equation is y=a(b)^{x} , where

  • a is the initial value
  • b is the growth/decay factor
  • If b > 1, then it is a growth factor
  • If 0 < b < 1, then it is a decay factor

Erica is a sheep farmer. She is having a problem with wolves attacking the flock. She starts with an initial 200 sheep and notices that the population is two-thirds of the previous year

∵ The population is decreased

∴ The equation is decay

∵ The population is two-thirds of the previous year

∴ The decay factor is \frac{2}{3}

∵ She starts with an initial 200 sheep

∴ the initial value is 200

∵ The decay equation is y=a(b)^{x} , where y represent the

   population in x years

∵ a = 200

∵ b = \frac{2}{3}

∴ y=200(\frac{2}{3})^{x}

The equation for the situation is y=200(\frac{2}{3})^{x}

∵ The population after x years is around 5 sheep

- Substitute y by 5 to find x

∵ 5=200(\frac{2}{3})^{x}

- Divide both sides by 200

∴ 0.025=(\frac{2}{3})^{x}

- Insert ㏒ for both sides

∴ log(0.025)=log(\frac{2}{3})^{x}

∴ log(0.025)=xlog(\frac{2}{3})

- Divide both sides by log(\frac{2}{3})

∴ 9.098 = x

∴ x is around 9 years

It will take around 9 years for her to have around 5 sheep

Learn more:

You can learn more about the equation  in brainly.com/question/10666510

#LearnwithBrainly

8 0
3 years ago
I turn my dial on my stove 45degrees from the start position if i continue to turn the dial, how many degrees further will i nww
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Answer:

315 degrees

Step-by-step explanation:

Assume that the dial is a perfect circle and therefore makes a full 360 degree rotation. If the dial is already turned 45 degrees, the rotation angle required to return all the way to the initial position is:

A = 360 - 45\\A=315\ degrees

You will need to rotate 315 degrees.

6 0
3 years ago
Help me on this math problem
Anon25 [30]

Answer:

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Explanation:

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4 0
3 years ago
Decide whether the pair of lines is parallel, perpendicular, or neither.
maw [93]

The lines are:  B) Perpendicular

Step-by-step explanation:

we have to convert both lines in slope-intercept form to find slopes

So,

3x - 6y = -13\\-6y = -3x-13\\\frac{-6y}{-6} = \frac{-3x-13}{-6}\\\frac{-6y}{-6} = \frac{-3x}{-6}+\frac{-13}{-6}\\y = \frac{1}{2} +\frac{13}{6}

Let m1 be the slope of first line

m_1 = \frac{1}{2}

For the second line:

18x + 9y = 5\\9y = -18x+5\\\frac{9y}{9} = \frac{-18x+5}{9}\\\frac{9y}{9} = \frac{-18}{9}x+\frac{5}{9}\\y = -2x+\frac{5}{9}

Let m2 be the slope of line 2

So,

If the lines are parallel, their slopes are equal

If the lines are perpendicular, product of their slopes is -1

We can see that

\frac{1}{2} * -2 = -1

Hence,

The lines are:  B) Perpendicular

Keywords: Slopes, Parallel lines

Learn more about slopes of lines at:

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