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3 years ago

113-5.[ 2 3-( 2 3+(6))]

Mathematics

1 answer:

dlinn [17]3 years ago

4 0

Answer:

143 should be correct

Step-by-step explanation:

hope this helps

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Based on the information from Harper's Index, 37 out of 100 adult Americans who did not attend college believe in extraterrestri

vazorg [7]

Answer: Yes, this indicate the proportion of adult americans that attended college and believe in extraterrestrials is higher than the proportion that did not attend college.

Step-by-step explanation:

Since we have given that

Hypothesis:

$H_0:p_1=p_2\\\\H_a:p_1>p_2$

n₁ = 100

x₁ = 37

So, $p_1=\dfrac{x_1}{n_1}=\dfrac{37}{100}=0.37$

n₂ = 100

x₂ =47

So, $p_2=\dfrac{47}{100}=0.47$

At 0.01 level of significance, z = 2.33

So, test statistic value would be

$z=\dfrac{p_1-p_2}{\sqrt{\dfrac{p_1(1-p_1)}{n_1}+\dfrac{p_2(1-p_2)}{n_2}}}\\\\z=\dfrac{0.37-0.47}{\sqrt{\dfrac{0.37\times 0.63}{100}+\dfrac{0.47\times 0.53}{100}}}\\\\z=-1.44$

Since, 2.33>-1.44

Hence, we will reject the null hypothesis.

Therefore, Yes, this indicate the proportion of adult americans that attended college and believe in extraterrestrials is higher than the proportion that did not attend college

4 0

3 years ago

How are zeros and the vertex of a quadratic function interpreted in the real world?

MrMuchimi

Pic isn’t loading sry

5 0

3 years ago

I don't understand what the answer is supposed to be, none of my answers match.

jolli1 [7]

The rational expression is the following

$\frac{\frac{x-1}{6xy}}{\frac{5}{2y}}$

By applying the sandwich rule:

we have

$\frac{\frac{x-1}{6xy}}{\frac{5}{2y}}=\frac{(x-1)(2y)}{(6xy)(5)}$

which gives

$\frac{\frac{x-1}{6xy}}{\frac{5}{2y}}=\frac{(x-1)(2y)}{(6xy)(5)}=\frac{(x-1)(2y)}{(2\cdot3xy)(5)}=\frac{(x-1)(2y)}{(3x\cdot2y)(5)}=\frac{x-1}{3x\cdot5}=\frac{x-1}{15x}$

then, the answer is option 2.

7 0

2 years ago

Use Stokes' Theorem to evaluate S curl F · dS. F(x, y, z) = 5y cos(z) i + ex sin(z) j + xey k, S is the hemisphere x2 + y2 + z2

Alenkinab [10]

By Stokes' theorem, the integral of the curl of $\vec F$ across $S$ is equal to the integral of $\vec F$ along the boundary of $S$ , call it $C$ . Parameterize $C$ by

$\vec r(t)=2\cos t\,\vec\imath+2\sin t\,\vec\jmath$

with $0\le t\le2\pi$ . So we have

$\displaystyle\iint_S(\nabla\times\vec F)\cdot\mathrm d\vec S=\int_C\vec F\cdot\mathrm d\vec r$

$=\displaystyle\int_0^{2\pi}(10\sin t\cos 0\,\vec\imath+e^{2\cos t}\sin0\,\vec\jmath+2\cos t\,e^{2\sin t}\,\vec k)\cdot(-2\sin t\,\vec\imath+2\cos t\,\vec\jmath)\,\mathrm dt$

$=\displaystyle\int_0^{2\pi}-20\sin^2t\,\mathrm dt$

$=\displaystyle-10\int_0^{2\pi}(1-\cos2t)\,\mathrm dt=\boxed{-20\pi}$

6 0

4 years ago

1. Find the value of x. The diagram is not to scale.

nika2105 [10]

Answer:

Step-by-step explanation:

As the angle in the bottom is shared and the 2 sides are proportional, one is 40 and 80 (times 2) and the other, 25 and 50 (times 2) so the triangles are similar so all we do is multiply 32 by 2 as its the rule. So the answer is 64.

3 0

3 years ago