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lana [24]
2 years ago
7

Luke can paint 91 portraits in a week how many portraits can Luke paint in for weeks

Mathematics
2 answers:
abruzzese [7]2 years ago
8 0

Answer:

364 paintings

Step-by-step explanation:

You should multiply the amount of paintings he makes per week times the amount of weeks (or 91 x 4), and you'll get your answer!

Basile [38]2 years ago
7 0

Answer:

91 * 4 = 364

Step-by-step explanation:

91 paintings per week times 4 weeks = 364 paintings after 4 weeks.

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The digits 3, 4, 5, 6, and 7 are arranged to form even, five-digit numbers. What is the hundreds digit in the largest of these n
GarryVolchara [31]
5 is in the hundreds column as the largest number would be 76  5(is the hundred)  43
4 0
3 years ago
Simplify 25^ - 1/2 <br><br>Please explain! I know the answer is 1/5 but why?
lisov135 [29]

(25)^{-\frac{1}{2} }

When the exponent is negative, you have to make the number a fraction(1 over the number).

For example:

25^{-2} = \frac{1}{25^{2} }

x^{-1} =\frac{1}{x^{1}  }

This gets rid of the negative, but it leaves the exponent

(25)^{-\frac{1}{2}}  = \frac{1}{25^{1/2}}

When an exponent is a fraction, it is the square root.

For example:

x^{\frac{1}{3}} =  \sqrt[3]{x}

x^{\frac{1}{2}}  =\sqrt{x}

x^{\frac{1}{4}}=\sqrt[4]{x}

So...

\frac{1}{25^{1/2}} = \frac{1}{\sqrt{25}  } = \frac{1}{5}

3 0
4 years ago
A spinner had four lettered sections. The table shows the results of an experiment spinning the pointer.
zhenek [66]

Answer:

Q 3/10    R 4/25    S 3/50  T 12/25

Step-by-step explanation:

Q 15/50    3/10

R 8/50     4/25

S 3/50    3/50

T 24/ 50   12/25

3 0
3 years ago
Read 2 more answers
Write a polynomial function f of least degree that has a leading coefficient of 1 and the given zeros. Write the function in sta
NeX [460]

Answer:

f(x)=x^3+(3+\sqrt{5})x^2+(6\sqrt{5}-18)x

or

f(x)=x^3+3x^2+\sqrt{5}x^2-18x+6\sqrt{5}x

Step-by-step explanation:

A polynomial function with 3 zeroes is going to be of degree 3, so we're going to have at least least 3 factors of the form x-a, where <em>a </em>is a zero of the function. For three zeroes <em>a</em>, <em>b</em>, and <em>c</em>, we'd have the factors x-a,\ x-b, and x-c, making our function look like

f(x)=(x-a)(x-b)(x-c)

Substituting our roots for a, b, and c:

f(x)=(x-(-6))(x-0)(x-(3-\sqrt{5}))\\=(x+6)(x)(x-3+\sqrt{5})

To write this function in standard form, we can expand from left to right:

f(x)=(x^2+6x)(x-3+\sqrt{5})\\=(x^2+6x)x-(x^2+6x)3+(x^2+6x)\sqrt{5}\\=x^3+6x^2-3x^2-18x+\sqrt{5}x^2+6\sqrt{5}x\\=x^3+3x^2+\sqrt{5}x^2-18x+6\sqrt{5}x

At this point, we could either leave it as is, or group the coefficients for the x^2 and x terms to get

f(x)=x^3+(3+\sqrt{5})x^2+(6\sqrt{5}-18)x

7 0
4 years ago
Given that <img src="https://tex.z-dn.net/?f=c%3D%5Cfrac%7B2d%2B1%7D%7B3d-1%7D" id="TexFormula1" title="c=\frac{2d+1}{3d-1}" alt
nata0808 [166]

Answer:

C = -6

Step-by-step explanation:

C = [2×1/4 + 1] ÷ [3×1/4 -1 ]

C = 3/2 ÷ -1/4

C = 3/2 × -4 = -6

C = 2d + 1 / 3d - 1

So, d = ( C + 1 ) / ( 3C - 2 )

7 0
3 years ago
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